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Top Forums Shell Programming and Scripting Passwordless sftp using a different user than the runtime user Post 302974025 by mady135 on Wednesday 25th of May 2016 03:26:15 AM
Old 05-25-2016
Passwordless sftp using a different user than the runtime user

I am running a shell script as user A. In that script I need to execute a sftp that would transfer the file using another user B.
I am using the below command:
Code:
sftp -oPort22 B@remote server

However, I am getting password prompts each time.
I have done the following:
  1. Added the public contents from local server to remoter servers /home/<user>/.ssh/authorized_keys.
  2. Tried changing permission of .ssh directory to both 700 and 744. Also, tried changing permission of authorized_keys to both 600 and 644.
Nothing has worked so far.

I guess, the command I am passing is correct as sftp is happening; but the passwordless authorization not working may be due to some file permissions issues.
Need your inputs
 

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SSH2_SFTP_LSTAT(3)							 1							SSH2_SFTP_LSTAT(3)

ssh2_sftp_lstat - Stat a symbolic link

SYNOPSIS
array ssh2_sftp_lstat (resource $sftp, string $path) DESCRIPTION
Stats a symbolic link on the remote filesystem without following the link. This function is similar to using the lstat(3) function with the ssh2.sftp:// wrapper in PHP 5 and returns the same values. PARAMETERS
o $sftp - o $path - Path to the remote symbolic link. RETURN VALUES
See the documentation for stat(3) for details on the values which may be returned. EXAMPLES
Example #1 Stating a symbolic link via SFTP <?php $connection = ssh2_connect('shell.example.com', 22); ssh2_auth_password($connection, 'username', 'password'); $sftp = ssh2_sftp($connection); $statinfo = ssh2_sftp_lstat($sftp, '/path/to/symlink'); $filesize = $statinfo['size']; $group = $statinfo['gid']; $owner = $statinfo['uid']; $atime = $statinfo['atime']; $mtime = $statinfo['mtime']; $mode = $statinfo['mode']; ?> SEE ALSO
ssh2_sftp_stat(3), lstat(3), stat(3). PHP Documentation Group SSH2_SFTP_LSTAT(3)
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