Not sure how 171 179 is coming as after 176 I couldn't see any thing continuous there. So if that is not the case then following may help you in same.
Output will be as follows.
If above code doesn't help you or you have some other conditions in your requirement please get back to us with more precise Input_file and all the conditions and expected sample Output_file too. EDIT: Changed code above a bit as it was no coming as per OP's expectation.
Thanks,
R. Singh
Last edited by RavinderSingh13; 05-25-2016 at 04:38 AM..
Reason: Changed code as Pravin pointed out that output was not OP's expectation. Thanks to Pravin.
This User Gave Thanks to RavinderSingh13 For This Post:
Hi Everyone,
a.txt
1272904667;1272904737;1
1272904747;1272904819;1
1272904810;1272904857;1
1272904889;1272904926;1
1272905399;1272905406;1
1272905411;1272905422;1
if i want to get the record, when the a.txt 1st field is between 1272904749 and 1272905399, any simple way by using awk,... (1 Reply)
Hi All.
I have a file that has an ID Number field....some of the ID Numbers are actual SSNs. ...does anyone know the range that SSNs may be...this is what I have found so far poking around SSN info sites....
greater than 001-01-0000 and less than 770-00-0000. Does anyone know this to be... (1 Reply)
out of a range of numbers, how can i pick out the number that is the closest to any arbitrary/random number that a user supplies?
say the range of numbers are between 1 - 90000. but that doesn't mean each number exist between 1 - 90000. the range of numbers could be for example:
1, 3, 4, 6,... (6 Replies)
Is there a way to create a loop that will output number starting from 0.1 to 10.0
0.1
0.2
0.3
0.4
0.5
..
...
10.0
This is what i tried.
for i in {1..50}; do printf -v i '%02d' $i ; echo "$i"; done
That will print
01
02
03
..
..
50 (9 Replies)
Is it possible to test against a varible within a ranges in a if statement.
ex.
if ];then
echo "not in range"
else
echo "number within range"
fi (8 Replies)
Hi
I want to get all numbers if number range is given as input.
Eg:
INPUT FILE
100-105
107
108-112
OUTPUT REQUIRED:
100 101 102 103 104 105
107
108 109 110 111 112
How can I do it using shell? :confused:
Thanks in advance. (11 Replies)
Hi there I am trying to generate a random number between 40 and 70 using the shell here is my code so far and it keeps going above 70. all help much appreciated!
comp=$(( RANDOM%70+40 ))
echo $comp (4 Replies)
Trying to use SED to replace numbers that fall into a range but can't seem to get the logic to work and am wondering if SED will do this. I have a file with the following numbers
3
26
20
5. For the numbers that are greater than zero and less than 25, SED would add the word range after the... (7 Replies)
Discussion started by: jimmyf
7 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)