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Shell Programming and Scripting
Bash script jumping too quickly to the next command - crash
Post 302973642 by tremblayemilie9 on Thursday 19th of May 2016 02:58:39 PM
05-19-2016
Hi,
thanks for the help.
Yoda;
I tried running the code #!/bin/bash -xv
and I got no information from it...
Maybe I am not doing it right but I see no text or output files from the problem.
Corona;
When this code is run all in one shot, I know that it stops at the step I mentioned above because the output files are not generated. BUT; when I run each steps one by one, it is all good... (
).
Instead, I would like it to run this next step where the ''pipeline'' just seem to run but doing nothing.
By crash, I mean it generates all the first files normally and then, it starts printing through the next steps way too quickly (one of them takes at least 1h normally) and that, up to the last step. I thens stays stuck there as if it was trying to process it still but I know it is not. I have waited for it, and I get no output files.
No error message appears and I am not able to make one appear...
.
I hope this is more clear...
thanks for the help.
Yoda;
I tried running the code #!/bin/bash -xv
and I got no information from it...
Maybe I am not doing it right but I see no text or output files from the problem.
Corona;
When this code is run all in one shot, I know that it stops at the step I mentioned above because the output files are not generated. BUT; when I run each steps one by one, it is all good... (
).Instead, I would like it to run this next step where the ''pipeline'' just seem to run but doing nothing.
By crash, I mean it generates all the first files normally and then, it starts printing through the next steps way too quickly (one of them takes at least 1h normally) and that, up to the last step. I thens stays stuck there as if it was trying to process it still but I know it is not. I have waited for it, and I get no output files.
No error message appears and I am not able to make one appear...
.I hope this is more clear...
Last edited by Scrutinizer; 05-19-2016 at 04:40 PM..
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LEARN ABOUT REDHAT
open
OPEN(1) Linux 1.x OPEN(1) NAME
open - start a program on a new virtual terminal (VT). SYNOPSIS
open [-c vtnumber] [-s] [-u] [-l] [-v] [--] command command_options DESCRIPTION
open will find the first available VT, and run on it the given command with the given command options, standard input, output and error are directed to that terminal. The current search path ($PATH) is used to find the requested command. If no command is specified then the envi- ronment variable $SHELL is used. OPTIONS -c vtnumber Use the given VT number and not the first available. Note you must have write access to the supplied VT for this to work. -s Switch to the new VT when starting the command. The VT of the new command will be made the new current VT. -u Figure out the owner of the current VT, and run login as that user. Suitable to be called by init. Shouldn't be used with -c or -l. -l Make the command a login shell. A - is prepended to the name of the command to be executed. -v Be a bit more verbose. -w wait for command to complete. If -w and -s are used together then open will switch back to the controlling terminal when the command completes. -- end of options to open. NOTE
If open is compiled with a POSIX (Gnu) getopt() and you wish to set options to the command to be run, then you must supply the end of options -- flag before the command. EXAMPLES
open can be used to start a shell on the next free VT, by using the command: open bash To start the shell as a login shell, use: open -l bash To get a long listing you must supply the -- separator: open -- ls -l SEE ALSO
login(1), doshell(8), switchto(1). AUTHOR
Jon Tombs <jon@gtex02.us.es or jon@robots.ox.ac.uk> -w idea from "sam". 19 Jul 1996 V1.4 OPEN(1)