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Top Forums Shell Programming and Scripting Extracting logs using gunzip awk and gzip Post 302972742 by pulkitbahl on Tuesday 10th of May 2016 09:15:45 AM
Old 05-10-2016
I need to take input of Date and Time from the user . It is not picking the correct values.

I have shared the manual line of code which is working and giving me correct response but I am not able to use it in shell script.



I need the below command to be used in shell script with various parameter taken from user

Code:
 gunzip -c FilePath/FileName_*.gz | awk '$0 > "[04/26/2016][03:30:00.000]" &&  $0 < "[04/26/2016][05:29:59.999]"'|\
 gzip >> FilePath/Outputfile.log.gz


parameter Date and Time..


Thanks for the response

---------- Post updated at 08:15 AM ---------- Previous update was at 08:15 AM ----------

Quote:
Originally Posted by RudiC
There might be some double quotes missing. What exactly is not working?
thnx kindly find my query above

Last edited by Don Cragun; 05-10-2016 at 07:58 PM.. Reason: Add CODE tags again.
 

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SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
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