Sponsored Content
Top Forums Shell Programming and Scripting How to pass variable from awk script to shell? Post 302970971 by Scrutinizer on Thursday 14th of April 2016 08:02:43 AM
Old 04-14-2016
@bakunin, that only works with kshand zsh (and in bash 4 but only with a special option and with job control disabled), since in other shells the part after the pipe is run in a subshell and the content of the variable will be lost afterwards...

Last edited by Scrutinizer; 04-14-2016 at 09:16 AM..
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Pass script variable value to AWK

HI all, some more mistery about AWK, I hope you can help me out: 1) I have a normal ksh script and sometime I call awk command. I set some variables in the script and I would like to use them up within AWK as well. Unfortunately AWK seems to forget all the variable values outside of its own... (1 Reply)
Discussion started by: BearCheese
1 Replies

2. UNIX for Dummies Questions & Answers

How to pass Shell script variable to awk

Hi, I have a shell script with an ambedded awk script. i need to pass a script variable to the awk script. Please help. Thanks in advance Himani (3 Replies)
Discussion started by: HIMANI
3 Replies

3. Shell Programming and Scripting

Is it possible to pass variable from awk to shell script

Hello experts, can I return a value from gawk to a shell script ? My script as follows, #Here I want the num value to shell script so that I can use later gawk ' { split($0,num,","); print num }' gawk -v no=$number '{print no}' file1 ... (3 Replies)
Discussion started by: user_prady
3 Replies

4. Shell Programming and Scripting

Is it possible to pass variable from awk to shell back

I am passing a varaible to from Shell to awk then I am doing some maniplation for that variable inside awk. I want that maniplated variable value back to shell , Is this possible .Please let me know. (12 Replies)
Discussion started by: unishiva
12 Replies

5. Shell Programming and Scripting

pass variable from awk to shell script

Hello Experts, Actually I was searching for a solution here in this forum , but didn't get what exactly I want . Is this possible to do in awk ? I am trying to do some thing like below in ksh script . Upto my knowledge I can pass shell script to awk with "-v " option. But I... (3 Replies)
Discussion started by: user_prady
3 Replies

6. Shell Programming and Scripting

How to pass a Awk variable to another script

Read parameter from a text file with one line which stored the date value like 20080831; below is the awk command I used gawk -F, "{getline RunDate;print $RunDate" text file When print $RunDate, it display 20080831 Would like to pass this variable to another script to use but not... (6 Replies)
Discussion started by: cbauw
6 Replies

7. UNIX for Dummies Questions & Answers

How to pass a variable from shell to awk

I know this topic has been dealt with previously, but the solutions I've seen don't work for me apparently. I need to pass a variable defined in the shell to one in awk: $ echo $var1 3 $ cat aaa aaa 1 bbb 2 ccc 3 ddd 4 eee 5I've tried this, without success: $ awk... (2 Replies)
Discussion started by: metaltree
2 Replies

8. Shell Programming and Scripting

Pass awk array variable to shell

Hi, all suppose I have following myfile (delimited by tab) aa bb cc dd ee ffand I have following awk command: awk 'BEGIN{FS="\t"}{AwkArrayVar_1=$1;AwkArrayVar_2=$2};END{for(i=0; i<NR; i++) print i, AwkArrayVar_1, AwkArrayVar_2,}' myfileMy question is: how can I assign the awk array... (7 Replies)
Discussion started by: littlewenwen
7 Replies

9. UNIX for Dummies Questions & Answers

Pass shell Variable to awk

Hello, May i please know how do i pass the shell variable to awk expression in the below script. It is returning null #!/bin/bash UNINUM=720922 UNINUM_DESC=`awk -F'|' -v UNINUM=$2 '/UNINUM/ {print $4}' datafile` echo $UNINUM_DESC datafile 4|First|720194|asdasdad 4|First|720735|asdasdsa... (8 Replies)
Discussion started by: Ariean
8 Replies

10. Shell Programming and Scripting

Unable to pass shell script variable to awk command in same shell script

I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist. diff=$1$2.diff id=$2 new=new_$diff echo "My id is $1" echo "I want to sync for user account $id" ##awk command I am using is as below cat $diff | awk... (2 Replies)
Discussion started by: Ashunayak
2 Replies
IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
All times are GMT -4. The time now is 05:04 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy