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Full Discussion: How to pass variable from awk script to shell?
Top Forums Shell Programming and Scripting How to pass variable from awk script to shell? Post 302970961 by Scrutinizer on Thursday 14th of April 2016 05:46:26 AM
Old 04-14-2016
You can do that by putting the entire awk script in a command substitution construct:

Code:
Rej=$(
  awk -v FS='|' -v OFS='|' '
  BEGIN {
     ........
  }
    ....
  }
  
  END {
    print Rej
  }
  }' f=$DMU_File $Predum_file > Validation.err
)


But the awk script should print to stderr instead of stdout:

Code:
........
        {    print "RECORD "NR": Mismatch Fould in Field:"fld_arr[i] " Actual value ("F[i]")...But Expected value ("k[i]")\n" > "/dev/stderr"[/COLOR]
             if (a != NR)
               {
                        Rej++;
                        a=NR;
                }
}
}
}
  END {
    print Rej
  }
}' f=$DMU_File $Predum_file 2> Validation.err
)

----
An alternative is to use

Code:
print "RECORD "NR": Mismatch Fould in Field:"fld_arr[i] " Actual value ("F[i]")...But Expected value ("k[i]")\n" [COLOR="Red"]>"validation.err"

and
Code:
}' f=$DMU_File $Predum_file


----
But perhaps if you post input and output samples, we could advise on how the script might be improved...
Last edited by Scrutinizer; 04-14-2016 at 11:38 AM..
 

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