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Full Discussion: Help with awk - variable
Top Forums Shell Programming and Scripting Help with awk - variable Post 302970070 by xcod3r on Friday 1st of April 2016 09:40:52 AM
Old 04-01-2016
Help with awk - variable
Hi All,

would appreciate help with the awk statement below, i not seeing the value of "color" as the variable in awk. not sure what i am missing

Code:
cat fruits
red:apples
yellow:banana


Code:
 cat fruits | awk '{
  if ( $1 == "red" ) {
                    color=red
           } else {
                    color=yellow
           }; split($0,a,":"); print "color of fruit found is", color } END { print "End of colour report"}'


output:

Code:
color of fruit found is
color of fruit found is
End of colour report!

 

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LEARN ABOUT PHP

imagecolortransparent

IMAGECOLORTRANSPARENT(3)						 1						  IMAGECOLORTRANSPARENT(3)

imagecolortransparent - Define a color as transparent

SYNOPSIS

       int imagecolortransparent (resource  $image, [int  $color])

DESCRIPTION

	Sets the transparent color in the given $image.

PARAMETERS

	      o $
		image -An image resource, returned by one of the image creation functions, such as imagecreatetruecolor(3).

	      o $color
		- A color identifier created with imagecolorallocate(3).

RETURN VALUES

	The  identifier of the new (or current, if none is specified) transparent color is returned. If $color is not specified, and the image has
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EXAMPLES

       Example #1

	      imagecolortransparent(3) example

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	      $black = imagecolorallocate($im, 0, 0, 0);

	      // Make the background transparent
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	      The above example will output something similar to:[NOT DISPLAYABLE MEDIA]Output of example : imagecolortransparent()

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PHP Documentation Group 												  IMAGECOLORTRANSPARENT(3)
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