Could you please try following and let me know if this works for you, though I haven't seen anything matching from your shown Input_file here.
As your Input_file is not having any of the content matching to your requirement so I couldn't test it, if your requirement is not matching to above code please show us more Input_file with expected output too. EDIT: Adding a non-one liner form for above solution as follows.
Thanks,
R. Singh
Last edited by RavinderSingh13; 03-28-2016 at 06:53 AM..
Reason: Added a non-one liner form of solution now.
Sorry if this has been posted before, I searched but not sure what I really want to do.
I have a file with records that show who has logged into my application:
2003-03-14:I:root: Log_mesg: registered servername:userid. (more after this)
I want to pull out the userid, date and time into... (2 Replies)
Hi all,
I have a flatfile
I would like to get ext = 7950 , how do I do that ?
if ($1 == "CTI-ProgramStart") {
ext = substr($9,index($9,"Extension")+11,4);
But why it is not working ???? Please help .
Thanks (1 Reply)
i have a variable 200612
the last two digits of this variable should be between 1 and 12, it should not be greater than 12 or less than 1 (for ex: 00 or 13,14,15 is not accepted)
how do i check for this conditions in a unix shell script.
thanks
Ram (3 Replies)
Hi
I have multiple files that name begins bidb_yyyymm. (yyyymm = current year month of file creation).
What I want to do is look at the files and where yyyymm is older than 1 month I want to remove the file from the server.
I was looking at looping through the files and getting the yyyymm... (2 Replies)
I have a variable '$test' that has the following string value:
$test = 123|456|789|0123
How would I select just the first element ('123') using awk.
Note: '|' is the delimiter, and the length of each field can vary.
Thanks,
- CB (3 Replies)
I have the following to find lines matching "COMPLETE" and extract parts of it using substr.
sed -n "/COMPLETE/p" 1.txt | awk 'BEGIN { FS = "\" } {printf"%s %s:%s \n", substr($3,17,3),substr($6,4,1), substr($7,4,1)}' | sort | uniq > temp.txt
Worked fine until the numbers in 2nd & 3rd substr... (5 Replies)
HI I am using awk and substr function to list out the directory names in the present working directory .
I am using below code
ls -l | awk '{ if ((substr($1,1,1)) -eq d) {print $9 }}'
But the problem is i am getting all the files and directories listed where as the requirement i wrote... (7 Replies)
Hi to all,
I'm here again, cause I need your help to solve another issue for me.
I have some files that have this name format: date_filename.csv
In my shell I must rename each file removing the date so that the file name is filename.csv
To do this I use this command:
fnames=`ls ${fname}|... (2 Replies)
Hello life savers!!
Is there any way to use substr in awk command for returning one part of a string from declared start and stop point?
I mean I know we have this:
substr(string, start, length)
Do we have anything like possible to use in awk ? :
substr(string, start, stop)
... (9 Replies)
Hi,
- In a file test.wmi
Col1 | firstName | lastName
4003 | toto_titi_CT- | otot_itit
- I want to have only ( colones $7,$13 and $15) with code 4003 and 4002. for colone $13 I want to have the whole name untill _CT- or _GC-
1- I used the command egrep with awk
#egrep -i... (2 Replies)
Discussion started by: georg2014
2 Replies
LEARN ABOUT DEBIAN
rdup-up
RDUP-UP(1) rdup RDUP-UP(1)NAME
rdup-up - update a directory tree with a rdup archive
SYNOPSIS
rdup-up [OPTION]... DIRECTORY
DESCRIPTION
With rdup-up you can update an (possibly) existing directory structure with a rdup archive.
The rdup archive has to be given to rdup-up's standard input.
Username and uids
rdup outputs both the username and uid, the receiving system (which may be a totally different system) checks if the username and uid
match. If the username and uid don't match the (numeric) uid is used on the file. The same holds true for the groupname and gid.
OPTIONS -n Do a dry-run and do not create anything on disk.
-t Create DIRECTORY (ala mkdir -p) if it does not exist.
-s N Strip N path components from a pathname. If the resulting pathname is empty after this operation it is skipped. Be careful however
with the following structure:
/foo
/foo/bar
/foo/bar/bla.txt
/foo/blork/bla.txt
With rdup-up -s2 this will leave:
<empty>
<empty>
/bla.txt
/bla.txt
And the last 'bla.txt' will overwrite the previous one, this will happen without warnings.
-r PATH
This option is related to the -s option, but works different. The string PATH is removed from (the beginning of) each pathname. With
-r /home/backup the pathname /home/backup/bin/mycmd becomes /bin/mycmd. The same could be done with -s 2, but then you need to count
the slashes. Note -s is always performed before -r.
-v Be more verbose and echo the processed files to standard output.
-vv Be even more verbose and echo processed file and the uid and gid information to standard output.
-T Show a table of contents of the rdup stream received (ala tar -tf -). With -T the directory argument is optional. -T unsets any
verbose (-v) options.
-h A short help message.
-V Show the version.
EXIT CODE
rdup-up return a zero exit code on success, otherwise 1 is returned.
AUTHOR
Written by Miek Gieben.
REPORTING BUGS
Report bugs to <miek@miek.nl>.
SEE ALSO
http:/www.miek.nl/projects/rdup/ is the main site of rdup. Also see rdup(1), rdup-tr(1) and rdup-backups(7).
COPYRIGHT
Copyright (C) 2005-2010 Miek Gieben. This is free software. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR
PURPOSE.
Licensed under the GPL version 3. See the file LICENSE in the source distribution of rdup.
1.1.11 13 Dec 2008 RDUP-UP(1)