(n)awk: print regex search output lines in one line
Hello.
I have been looking high and low for the solution for this. I seems there should be a simple answer, but alas.
I have a big xml file, and I need to extract certain information from specific items. The information I need can be found between a specific set of tags. let's call them <tag></tag>. Doing a regex lookup yields 4 lines of text, which I need to be 1 line, and this has to happen with every snippet that's between those tags (about 700 or so <tag></tag> elements in the xml file).
So, if I do this:
the output I get is:
The output I need:
Note: I am in a very secure environment, so I cannot install anything, so I only have the regular awk/nawk/gawk and sed that comes with Solaris 11.
suppose i have one file
file A
18
24
30
35
38
45
55
Another file file B
08_46 A 16 V -0.36 0.23 E : 1.41
08_46 A 17 D -1.04 0.22 E : 0.84
08_46 A 18 Q -0.49 0.12 E : 0.06
08_46 A 19 G 0.50 0.14 E : 0.05
08_46 A 20 V ... (5 Replies)
Hello,
Can anybody help me to correct my sed syntax to find the string and print previous two lines and current line and next one line.
i am using string as "testing"
netstat -v | sed -n -e '/test/{x;2!p;g;$!N;p;D;}' -e h
i am able to get the previous line current line next line but... (1 Reply)
Hello.
I've been banging my head against walls trying to search a comma delimited file, using awk. I'm trying to search a "column" for a specific parameter, if it matches, then I'd like to print the whole line.
I've read in multiple texts:
awk -F, '{ if ($4 == "string") print $0 }'... (2 Replies)
I have multiple config files where I need to pull the ip address from loopback3. The format is the same in every file, the ip is the second line after interface loopback3.
interface loopback2 loopback
description router ID
ip address 192.168.1.1
interface loopback3 loopback
description... (3 Replies)
All I want is to look for the pattern in the file...If I found it at # places... I want print lines after those pattern(line) until I find a blank line.
Log EXAMPLE :
MT:Exception caught
The following Numbers were affected:
1234
2345
2346
Error
java.lang.InternalError:... (3 Replies)
I have a text file ( basically a log file) and i have 2 words (alpha, beta),
Now i want to search these two words in one line and then print next 15 lines in a temp file. there would be many lines with alpha and beta But I need only last occurrence with "alpha" and "beta" and next 15 lines.
... (4 Replies)
if the first string matches then print the previous line and current line and also print the following lines if the other string search matches.
Input
------
TranTime 2012 10 12
The Record starts here
Accountnumber: 4632473431274
TxnCode 323
TranID 329473242834
ccsdkcnsdncskd... (7 Replies)
Hi,
I am using the following code to fetch lines that are generated in last 1 hr . Hence, I am using date function to calculate -last 1 hr & the current hr and then somehow use awk (or sed-if someone could guide me better)
with some regex pattern.
dt_1=`date +%h" "%d", "%Y\ %l -d "1 hour... (10 Replies)
Dear all
I want to search special string in file and then print next all line in one line until blank lines come. Help me plz for same. My input file and desire op file is as under.
i/p file:
A1/EXT "BSCABD1_21233G1" 757 130823 1157
RADIO X-CEIVER ADMINISTRATION
BTS EXTERNAL FAULT
... (7 Replies)
GOODNUMBERS="1 2 3 4 5 6 3 3 34 34 5 66 12"
BADNUMBERS="7 3 12 5 66"
for eachnum in `echo ${GOODNUMBERS}`
do
echo ${BADNUMBERS} | gawk -v threshold=${eachnum} '$1 != threshold'
done
what im trying to do with the above is, i want to print numbers that are in the GOODNUMBERS... (10 Replies)
Discussion started by: SkySmart
10 Replies
LEARN ABOUT X11R4
regex
regex(1F) FMLI Commands regex(1F)NAME
regex - match patterns against a string
SYNOPSIS
regex [-e] [ -v "string"] [ pattern template] ... pattern [template]
DESCRIPTION
The regex command takes a string from the standard input, and a list of pattern / template pairs, and runs regex() to compare the string
against each pattern until there is a match. When a match occurs, regex writes the corresponding template to the standard output and
returns TRUE. The last (or only) pattern does not need a template. If that is the pattern that matches the string, the function simply
returns TRUE. If no match is found, regex returns FALSE.
The argument pattern is a regular expression of the form described in regex(). In most cases, pattern should be enclosed in single quotes
to turn off special meanings of characters. Note that only the final pattern in the list may lack a template.
The argument template may contain the strings $m0 through $m9, which will be expanded to the part of pattern enclosed in ( ... )$0 through
( ... )$9 constructs (see examples below). Note that if you use this feature, you must be sure to enclose template in single quotes so
that FMLI does not expand $m0 through $m9 at parse time. This feature gives regex much of the power of cut(1), paste(1), and grep(1), and
some of the capabilities of sed(1). If there is no template, the default is $m0$m1$m2$m3$m4$m5$m6$m7$m8$m9.
OPTIONS
The following options are supported:
-e Evaluates the corresponding template and writes the result to the standard output.
-v "string" Uses string instead of the standard input to match against patterns.
EXAMPLES
Example 1: Cutting letters out of a string
To cut the 4th through 8th letters out of a string (this example will output strin and return TRUE):
`regex -v "my string is nice" '^.{3}(.{5})$0' '$m0'`
Example 2: Validating input in a form
In a form, to validate input to field 5 as an integer:
valid=`regex -v "$F5" '^[0-9]+$'`
Example 3: Translating an environment variable in a form
In a form, to translate an environment variable which contains one of the numbers 1, 2, 3, 4, 5 to the letters a, b, c, d, e:
value=`regex -v "$VAR1" 1 a 2 b 3 c 4 d 5 e '.*' 'Error'`
Note the use of the pattern '.*' to mean "anything else".
Example 4: Using backquoted expressions
In the example below, all three lines constitute a single backquoted expression. This expression, by itself, could be put in a menu defini-
tion file. Since backquoted expressions are expanded as they are parsed, and output from a backquoted expression (the cat command, in this
example) becomes part of the definition file being parsed, this expression would read /etc/passwd and make a dynamic menu of all the login
ids on the system.
`cat /etc/passwd | regex '^([^:]*)$0.*$' '
name=$m0
action=`message "$m0 is a user"`'`
DIAGNOSTICS
If none of the patterns match, regex returns FALSE, otherwise TRUE.
NOTES
Patterns and templates must often be enclosed in single quotes to turn off the special meanings of characters. Especially if you use the
$m0 through $m9 variables in the template, since FMLI will expand the variables (usually to "") before regex even sees them.
Single characters in character classes (inside []) must be listed before character ranges, otherwise they will not be recognized. For exam-
ple, [a-zA-Z_/] will not find underscores (_) or slashes (/), but [_/a-zA-Z] will.
The regular expressions accepted by regcmp differ slightly from other utilities (that is, sed, grep, awk, ed, and so forth).
regex with the -e option forces subsequent commands to be ignored. In other words, if a backquoted statement appears as follows:
`regex -e ...; command1; command2`
command1 and command2 would never be executed. However, dividing the expression into two:
`regex -e ...``command1; command2`
would yield the desired result.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO awk(1), cut(1), grep(1), paste(1), sed(1), regcmp(3C), attributes(5)SunOS 5.10 12 Jul 1999 regex(1F)