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Full Discussion: awk colon separated items
Top Forums UNIX for Dummies Questions & Answers awk colon separated items Post 302968822 by janshamsani on Tuesday 15th of March 2016 12:13:17 AM
Old 03-15-2016
awk colon separated items

Hi,

I need to filter my data based on items in column 23. Column 1 until column 23 are tab separated. This is how column 23 looks like:

PRIMARY=<0/1:504:499,5:.:.:.:0.01:1:15:.>

I want to extract lines if items 7 (separated by : ) in column 23 are more than 0.25 . In example above , item $7 is 0.01 .

Previously, I just need to count items that pass my criteria . I used this code and it worked perfectly .

Code:
awk -F"\t" 'NR>1 {split($23,a,":"); count[a[7]]++} END {for (i in count) if(i>0.25) sum +=count[i]; print sum}' file.tsv


Now , I need to extract information in all columns too. So i tried to modify the code but I did not work.

Code:
awk -F"\t" 'NR>1 {split($23,a,":"); count[a[7]]++} END {for (i in count) if(i>0.25) print $0}' file.tsv

The output that I want would look the same as my input file, but only with lines that pass the filter.

I have attached the sample input file
 

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DB2_FIELD_TYPE(3)							 1							 DB2_FIELD_TYPE(3)

db2_field_type - Returns the data type of the indicated column in a result set

SYNOPSIS
string db2_field_type (resource $stmt, mixed $column) DESCRIPTION
Returns the data type of the indicated column in a result set. PARAMETERS
o $stmt - Specifies a statement resource containing a result set. o $column - Specifies the column in the result set. This can either be an integer representing the 0-indexed position of the column, or a string containing the name of the column. RETURN VALUES
Returns a string containing the defined data type of the specified column. If the specified column does not exist in the result set, db2_field_type(3) returns FALSE. SEE ALSO
db2_field_display_size(3), db2_field_name(3), db2_field_num(3), db2_field_precision(3), db2_field_scale(3), db2_field_width(3). PHP Documentation Group DB2_FIELD_TYPE(3)
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