Sponsored Content
Top Forums Shell Programming and Scripting Loop with multiple delimited variables Post 302968438 by rdrtx1 on Wednesday 9th of March 2016 12:38:40 PM
Old 03-09-2016
try something like:
Code:
var1=1,23,234
var2=a,ab,xyz
var3=0,0,0

IFS="," arr1=($var1)
IFS="," arr2=($var2)
IFS="," arr3=($var3)

seq 0 2 | while read i
do
   echo " insert into table (${arr1[$i]}, '${arr2[$i]}', ${arr3[$i]});"
done

This User Gave Thanks to rdrtx1 For This Post:
 

9 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

for loop with multiple variables ?

I have a script which selects two 'sets' of system LVM device files from a tabular file 'mapfile' using awk : LIVELV=`awk '{print($1)}' mapfile` BCVLV=`awk '{print($3)}' mapfile` I wanted to pass these 'sets' into an LVM command 'loop' along the lines of : lvmerge $BCVLV $LIVELV ie.... (3 Replies)
Discussion started by: fosterian
3 Replies

2. Shell Programming and Scripting

While loop with Multiple variables

Hi , I am trying to write a script in kshell with while loop ,its like count=1 count_cmp=1 while ; do tail -$count tempfile | head -1 > tempstring ....... done However i get CIF.sh: line 33: ' I have checked thetrailing spaces , not sure what is... (4 Replies)
Discussion started by: amit1_x
4 Replies

3. UNIX for Dummies Questions & Answers

multiple variables in for loop

hi, I want an equivalent for loop for this C code in unix shell script... for(int i,int j;i<5;i++,j++) { } Please reply soon Regards Navjot (1 Reply)
Discussion started by: navjotsingh
1 Replies

4. UNIX for Dummies Questions & Answers

For Loop for a list of tab delimited variables

Hello, I need to run a command for a set of input variables that are present in a tab delimited file, a sample of which is shown below: 1 3749 1 4129 1 5980 2 6201 2 9925 2 6894 3 1338 3 6477 3 6242 3 3632 Every row represents the two input values... (2 Replies)
Discussion started by: Gussifinknottle
2 Replies

5. Shell Programming and Scripting

How to use for/while loop with multiple variables?

Hi, I have two variables like below which will always be of the same size a=1:2:3 b=A:B:C I need to use a for/while loop that will have both the variables available. I cannot use an array here and will probably might iterate through the variable as echo $a | tr ':' '\n' and thus iterate... (5 Replies)
Discussion started by: Elizabeth H
5 Replies

6. UNIX for Dummies Questions & Answers

Multiple variables to be passed in a loop

Hi, I need to pass the multiple values of src1 to another variable. I managed to print it but not sure how to assign it to a variable in a loop. src1=01,02,03 echo $src1|awk 'BEGIN {FS=","} {for(i=1;i<=NF;i++) print $i}' I need to pass the value as src2=01 src2=02 src2=03 Thanks... (4 Replies)
Discussion started by: shash
4 Replies

7. UNIX for Dummies Questions & Answers

Reading multiple variables in a loop

Hi, I managed to read and print variable as shown in the below code. table_name=table1,table2,table3 i=0 IFS="," for i in $table_name do echo $i done Is there a way how I can read more than one variable. For example I need to read 2 variables and populate the output... (6 Replies)
Discussion started by: shash
6 Replies

8. Shell Programming and Scripting

Multiple variables using awk and for loop for web form submission

Hi My goal is to fill an HTML form and submit. What I have managed to do: 1. curl command to fill up the form and submit 2. a file which has the input curl command: curl -v -b cookie.txt -d __CSRFToken__=dc23d5da47953b3b390ec68d972af10380908b14 -d do=create -d a=open -d... (10 Replies)
Discussion started by: zorrox
10 Replies

9. UNIX for Beginners Questions & Answers

Displaying multiple variables in for loop

Hi! I've run into a problem where my variables are displayed in the wrong order. Basically I'm supposed to use a file that has information like this username:firstname:lastname:etc:etc. What I'm interested in doing is reformating it into a something more like this: username lastname,... (2 Replies)
Discussion started by: reindeermountai
2 Replies
DEBUG_ZVAL_DUMP(3)							 1							DEBUG_ZVAL_DUMP(3)

debug_zval_dump - Dumps a string representation of an internal zend value to output

SYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...]) DESCRIPTION
Dumps a string representation of an internal zend value to output. PARAMETERS
o $variable - The variable being evaluated. RETURN VALUES
No value is returned. EXAMPLES
Example #1 debug_zval_dump(3) example <?php $var1 = 'Hello World'; $var2 = ''; $var2 =& $var1; debug_zval_dump(&$var1); ?> The above example will output: &string(11) "Hello World" refcount(3) Note Beware the refcount The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3). This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a slightly modified version of the above example: Example #2 <?php $var1 = 'Hello World'; $var2 = ''; $var2 =& $var1; debug_zval_dump($var1); // not passed by reference, this time ?> The above example will output: string(11) "Hello World" refcount(1) Why refcount(1)? Because a copy of $var1 is being made, when the function is called. This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value): Example #3 <?php $var1 = 'Hello World'; debug_zval_dump($var1); ?> The above example will output: string(11) "Hello World" refcount(2) A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening? When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti- mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made, but only at the moment of writing. This is known as "copy on write." So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call. SEE ALSO
var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans). PHP Documentation Group DEBUG_ZVAL_DUMP(3)
All times are GMT -4. The time now is 05:23 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy