I have a script which selects two 'sets' of system LVM device files from a tabular file 'mapfile' using awk :
LIVELV=`awk '{print($1)}' mapfile`
BCVLV=`awk '{print($3)}' mapfile`
I wanted to pass these 'sets' into an LVM command 'loop' along the lines of :
lvmerge $BCVLV $LIVELV
ie.... (3 Replies)
Hi ,
I am trying to write a script in kshell with while loop ,its like
count=1
count_cmp=1
while ; do
tail -$count tempfile | head -1 > tempstring
.......
done
However i get CIF.sh: line 33: '
I have checked thetrailing spaces , not sure what is... (4 Replies)
Hello,
I need to run a command for a set of input variables that are present in a tab delimited file, a sample of which is shown below:
1 3749
1 4129
1 5980
2 6201
2 9925
2 6894
3 1338
3 6477
3 6242
3 3632
Every row represents the two input values... (2 Replies)
Hi,
I have two variables like below which will always be of the same size
a=1:2:3
b=A:B:C
I need to use a for/while loop that will have both the variables available. I cannot use an array here and will probably might iterate through the variable as echo $a | tr ':' '\n' and thus iterate... (5 Replies)
Hi,
I need to pass the multiple values of src1 to another variable. I managed to print it but not sure how to assign it to a variable in a loop.
src1=01,02,03
echo $src1|awk 'BEGIN {FS=","} {for(i=1;i<=NF;i++) print $i}'
I need to pass the value as
src2=01
src2=02
src2=03
Thanks... (4 Replies)
Hi,
I managed to read and print variable as shown in the below code.
table_name=table1,table2,table3
i=0
IFS=","
for i in $table_name
do
echo $i
done
Is there a way how I can read more than one variable. For example I need to read 2 variables and populate the output... (6 Replies)
Hi
My goal is to fill an HTML form and submit.
What I have managed to do:
1. curl command to fill up the form and submit
2. a file which has the input
curl command:
curl -v -b cookie.txt -d __CSRFToken__=dc23d5da47953b3b390ec68d972af10380908b14 -d do=create -d a=open -d... (10 Replies)
Hi!
I've run into a problem where my variables are displayed in the wrong order. Basically I'm supposed to use a file that has information like this username:firstname:lastname:etc:etc.
What I'm interested in doing is reformating it into a something more like this: username lastname,... (2 Replies)
Discussion started by: reindeermountai
2 Replies
LEARN ABOUT PHP
debug_zval_dump
DEBUG_ZVAL_DUMP(3) 1 DEBUG_ZVAL_DUMP(3)debug_zval_dump - Dumps a string representation of an internal zend value to outputSYNOPSIS
void debug_zval_dump (mixed $variable, [mixed $...])
DESCRIPTION
Dumps a string representation of an internal zend value to output.
PARAMETERS
o $variable
- The variable being evaluated.
RETURN VALUES
No value is returned.
EXAMPLES
Example #1
debug_zval_dump(3) example
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump(&$var1);
?>
The above example will output:
&string(11) "Hello World" refcount(3)
Note
Beware the refcount
The refcount value returned by this function is non-obvious in certain circumstances. For example, a developer might expect the
above example to indicate a refcount of 2. The third reference is created when actually calling debug_zval_dump(3).
This behavior is further compounded when a variable is not passed to debug_zval_dump(3) by reference. To illustrate, consider a
slightly modified version of the above example:
Example #2
<?php
$var1 = 'Hello World';
$var2 = '';
$var2 =& $var1;
debug_zval_dump($var1); // not passed by reference, this time
?>
The above example will output:
string(11) "Hello World" refcount(1)
Why refcount(1)? Because a copy of $var1 is being made, when the function is called.
This function becomes even more confusing when a variable with a refcount of 1 is passed (by copy/value):
Example #3
<?php
$var1 = 'Hello World';
debug_zval_dump($var1);
?>
The above example will output:
string(11) "Hello World" refcount(2)
A refcount of 2, here, is extremely non-obvious. Especially considering the above examples. So what's happening?
When a variable has a single reference (as did $var1 before it was used as an argument to debug_zval_dump(3)), PHP's engine opti-
mizes the manner in which it is passed to a function. Internally, PHP treats $var1 like a reference (in that the refcount is
increased for the scope of this function), with the caveat that if the passed reference happens to be written to, a copy is made,
but only at the moment of writing. This is known as "copy on write."
So, if debug_zval_dump(3) happened to write to its sole parameter (and it doesn't), then a copy would be made. Until then, the
parameter remains a reference, causing the refcount to be incremented to 2 for the scope of the function call.
SEE ALSO var_dump(3), debug_backtrace(3), References Explained, References Explained (by Derick Rethans).
PHP Documentation Group DEBUG_ZVAL_DUMP(3)