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Top Forums Shell Programming and Scripting Bash regex evaluation not workin Post 302968298 by lramirev on Monday 7th of March 2016 05:30:04 PM
Old 03-07-2016
Bash regex evaluation not workin

I'm building a script that may received start and end date as parameters. I whant to make it as flexible as possible so I'm accepting epoch and date in a way that "date --date=" command may accept. In order to know if parameter provided is an epoc or a "date --date=" string I evaluate if the value is a number. For this a built a function:

Code:
function isNumber ()
{ [[ "$1" =~ "^[0-9]+$" ]] && echo true || echo false
}

The intended use of the funtion is as following

Code:
while getopts :e:F:G:hmo:r:s:vZ dOpts
do
        case $dOpts in
        "e")    if $(isNumber "$OPTARG")
                then
                        dEnd="$OPTARG"
                else
                        dEnd=$(date --date="$OPTARG" +%s)
                fi
                ;;
        "s")    if $(isNumber "$OPTARG")
                then
                        dStart="$OPTARG"
                else
                        dStart=$(date --date="$OPTARG" +%s)
                fi
                ;;
        esac
done
shift $((OPTIND-1))

I'm running on:
Code:
# cat /proc/version
Linux version 2.6.32-279.19.1.el6.x86_64 (mockbuild@x86-001.build.bos.redhat.com) (gcc version 4.4.6 20120305 (Red Hat 4.4.6-4) (GCC) ) #1 SMP Sat Nov 24 14:35:28 EST 2012

And my bash version is:
Code:
# rpm -qa bash
bash-4.1.2-9.el6_2.x86_64

Every time I evaluate the function it returns false. I made this test on my console and it do return false every time.

Code:
# isNumber e-1month
false
# isNumber 1420088400
false
# [[ 1420088400 =~ '[0-9].' ]] && echo true || echo false
false
# [[ 1420088400 =~ '[0-9]+' ]] && echo true || echo false
false
# [[ "1420088400" =~ '^[0-9]+$' ]] && echo true || echo false
false

What I'm I doing wrong with this redex evaluation? I'm I missing an option on bash? This is my invocation line of the script
Code:
#!/bin/bash

Thank you for attention to this message.
 

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IS_STRING(3)								 1							      IS_STRING(3)

is_string - Find whether the type of a variable is string

SYNOPSIS
bool is_string (mixed $var) DESCRIPTION
Finds whether the type given variable is string. PARAMETERS
o $var - The variable being evaluated. RETURN VALUES
Returns TRUE if $var is of type string, FALSE otherwise. EXAMPLES
Example #1 is_string(3) example <?php $values = array(false, true, null, 'abc', '23', 23, '23.5', 23.5, '', ' ', '0', 0); foreach ($values as $value) { echo "is_string("; var_export($value); echo ") = "; echo var_dump(is_string($value)); } ?> The above example will output: is_string(false) = bool(false) is_string(true) = bool(false) is_string(NULL) = bool(false) is_string('abc') = bool(true) is_string('23') = bool(true) is_string(23) = bool(false) is_string('23.5') = bool(true) is_string(23.5) = bool(false) is_string('') = bool(true) is_string(' ') = bool(true) is_string('0') = bool(true) is_string(0) = bool(false) SEE ALSO
is_float(3), is_int(3), is_bool(3), is_object(3), is_array(3). PHP Documentation Group IS_STRING(3)
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