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Top Forums UNIX for Dummies Questions & Answers Extract name from path and change output Post 302966650 by giuliangiuseppe on Monday 15th of February 2016 06:02:39 AM
Old 02-15-2016
Extract name from path and change output

Dear All,

I would like to extract the file name without extension form a variable...
In particular I have a command like this one:

Code:
for file in path/to/file/example_number.ext
do something -input $file -output ${file%_number.ext}.new
done

means that in variable $file are saved all the path and the files.

Now, the output
Code:
-output  ${file%_number.ext}.new

save the output file
Code:
example.new

in:
Code:
path/to/file/

What I would like instead is to extract just the file name and output the result in a new/path

Code:
for file in path/to/file/example_number.ext
do something -input $file -output "new/path/example.new"
done

so the output file will be in

Code:
new/path/

and name
Code:
example.new

Obviously I have multiple files in the folder.

Hope is clear
Thanks for any help!

Best


Giuliano
 

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CPANPLUS::Internals::Extract(3pm)			 Perl Programmers Reference Guide			 CPANPLUS::Internals::Extract(3pm)

NAME
CPANPLUS::Internals::Extract - internals for archive extraction SYNOPSIS
### for source files ### $self->_gunzip( file => 'foo.gz', output => 'blah.txt' ); ### for modules/packages ### $dir = $self->_extract( module => $modobj, extractdir => '/some/where' ); DESCRIPTION
CPANPLUS::Internals::Extract extracts compressed files for CPANPLUS. It can do this by either a pure perl solution (preferred) with the use of "Archive::Tar" and "Compress::Zlib", or with binaries, like "gzip" and "tar". The flow looks like this: $cb->_extract Delegate to Archive::Extract METHODS
$dir = _extract( module => $modobj, [perl => '/path/to/perl', extractdir => '/path/to/extract/to', prefer_bin => BOOL, verbose => BOOL, force => BOOL] ) "_extract" will take a module object and extract it to "extractdir" if provided, or the default location which is obtained from your config. The file name is obtained by looking at "$modobj->status->fetch" and will be parsed to see if it's a tar or zip archive. If it's a zip archive, "__unzip" will be called, otherwise "__untar" will be called. In the unlikely event the file is of neither format, an error will be thrown. "_extract" takes the following options: module A "CPANPLUS::Module" object. This is required. extractdir The directory to extract the archive to. By default this looks something like: /CPANPLUS_BASE/PERL_VERSION/BUILD/MODULE_NAME prefer_bin A flag indicating whether you prefer a pure perl solution, ie "Archive::Tar" or "Archive::Zip" respectively, or a binary solution like "unzip" and "tar". perl The path to the perl executable to use for any perl calls. Also used to determine the build version directory for extraction. verbose Specifies whether to be verbose or not. Defaults to your corresponding config entry. force Specifies whether to force the extraction or not. Defaults to your corresponding config entry. All other options are passed on verbatim to "__unzip" or "__untar". Returns the directory the file was extracted to on success and false on failure. perl v5.18.2 2014-01-06 CPANPLUS::Internals::Extract(3pm)
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