Hi
I am having date as a string in DDMMYYYY format(07082008) in a variable say cdate. I want to Convert it into DD Month YYYY format(7 August 2008). Could someone help. Thanks in Advance. (2 Replies)
I have a file which has 100k+ records like this
abc,05-JUN-1974,def,lkj,aaa
def,11-SEP-1975,ghj,dis,dea
I want to convert ex 05-JUN-1974 to 06/05/1974
Please help me with awk script to convert the whole file into MM-DD-YYYY
Thank you! (2 Replies)
In my shell script i have a variable which stores date in the format of YYYYMMDD. Is there any way to format this value to MM/DD/YYYY.
Thanks. (8 Replies)
Hi all
I have some pipe-separated data in the form:
5/12/2008 00:00:00|31/1/2009 00:00:00|SOMESTUFF|OTHERSTUFF
12/31/2008 00:00:00|15/1/2009 00:00:00|MORESTUFF|REMAININGSTUFF
1/1/1023 00:00:00|16/5/2047 00:00:00|THEREST|YETMORE
I need to zero-pad the single-digit days and months, using... (3 Replies)
My csv has data like this
x,x,3452,2/18/1986,abc
x,g,19711,1/24/1986,abc
i want to replace date in the following format YYYY-mm-dd
how do i convert using awk script ? (8 Replies)
How can I convert any user inputted date into yyyy/mm/dd ?
For example user can input date one of the following 20120121 , 2012-01-21 ,01/21/2012,01/21/2012 etc
But I need to convert any of the date entered by user into yyyy/mm/dd (2012/01/2012). Any suggestion. Thanks in advance
this is... (1 Reply)
Hi All,
I have file like
“April 10, 2013”,”raj”
“April 29, 2013”,”raj1”
Output :
“2013/04/10”,”raj”
“2013/04/29”,”raj1”
Please help me how to do... (9 Replies)
Hello All,
I have a date in DD/MM/YYYY format. I am trying to convert this into unix timestamp. I have tried following:
date -d $mydate +%s
where mydate = 23/12/2016 00:00:00
I am getting following error:
date: extra operand `+%s'
Try `date --help' for more information.
... (1 Reply)
How to convert mmm-yy to mm/dd/yyyy format in unix ?
example:
Jan-99 to 01/01/1999
Jan-00 to 01/01/2000
Jan-25 to 01/01/2025
Dec-99 to 01/12/1999
Dec-00 to 01/12/2000
Dec-25 to 01/12/2025
YY anything between 00-50 should be 2000-2050
YY anything between 51-99 should be 1951-1999
... (2 Replies)
Discussion started by: gksenthilkumar
2 Replies
LEARN ABOUT SUSE
bashbug
BASHBUG(1) General Commands Manual BASHBUG(1)NAME
bashbug - report a bug in bash
SYNOPSIS
bashbug [--version] [--help] [email-address]
DESCRIPTION
bashbug is a shell script to help the user compose and mail bug reports concerning bash in a standard format. bashbug invokes the editor
specified by the environment variable EDITOR on a temporary copy of the bug report format outline. The user must fill in the appropriate
fields and exit the editor. bashbug then mails the completed report to bug-bash@gnu.org, or email-address. If the report cannot be
mailed, it is saved in the file dead.bashbug in the invoking user's home directory.
The bug report format outline consists of several sections. The first section provides information about the machine, operating system,
the bash version, and the compilation environment. The second section should be filled in with a description of the bug. The third sec-
tion should be a description of how to reproduce the bug. The optional fourth section is for a proposed fix. Fixes are encouraged.
ENVIRONMENT
bashbug will utilize the following environment variables if they exist:
EDITOR Specifies the preferred editor. If EDITOR is not set, bashbug defaults to emacs.
HOME Directory in which the failed bug report is saved if the mail fails.
TMPDIR Directory in which to create temporary files and directories.
SEE ALSO bash(1)AUTHORS
Brian Fox, Free Software Foundation
bfox@gnu.org
Chet Ramey, Case Western Reserve University
chet@po.cwru.edu
GNU Bash-4.0 1998 July 30 BASHBUG(1)