This is my Scenario:
I wanted to check if a particular name or pattern is present in a file based of that rest of the program should proceed.
I want to print '0' if no matching found.
The above command is giving an output where a tab space is present due to which I am not able to do a condition.
Code:
if [[ $v_File_Count == 0]]; then
xyz...
fi
Tried to remove the "<Tab Space>" as below but no use
Code:
v_File_Count=`grep -i "$v_Name_Pattern" $File_Path/Master_File_List.txt | wc -l | tr " " ""`
## Below code is not print any value if there is no record -- I want '0' if no record
v_File_Count=`grep -i "$v_Name_Pattern" $File_Path/Master_File_List.txt | awk '{print NR}'`
v_File_Count=`grep -i "$v_Name_Pattern" $File_Path/Master_File_List.txt | sed -n '$='`
Sample Input:
File = Master_File_List.txt
Code:
abcd.txt
xyz.txt
lmno.txt
Command:
Code:
v_File_Count=`grep -i "$v_Name_Pattern" $File_Path/Master_File_List.txt | sed -n '$='
** Anycode
Expected Output: ( If there are no matching pattern, 0 should be returned i.e., v_File_Count should have value '0')
Do share your ideas and suggestion
Last edited by Scrutinizer; 12-30-2015 at 09:07 AM..
Reason: quote tags -> code tags
Hi,
I need a command that would let ls show number of lines in each file rather than file size in KBs.
I tried using wc -l as a source of input to ls but I found a problem cutting the file name since wc generates a space delimited list.
Any suggestions?
Thanks.
GmMike. (1 Reply)
Hi,
I have a text file contaning around 150 lines, each line is a hostname.
I want to read 4 lines/hostnames and save those 4 lines to a seperate file.
say the big file is /files/bigfile and I want to have a lot of files in /files named
/files/smallfile.1 , /files/smallfile.2 and so on...
... (1 Reply)
Hi
How do I find number of lines of a file? Below commands returned 0. But, the file is showing 20 lines when I open it in editplus tool. Each line contains 601 columns. Please advise
I want to incorporate some word at the begining of each of those 20 lines
-Somesh
$ wc -l <... (2 Replies)
Hi,
I am using below command to display the number of line, but its returning no of lines along with file name.
But i want only no of line in the variable p.
Please help me on this?
p=`wc -l "text file"`
echo "$p" (6 Replies)
Dear Members,
I want to count the number of lines in a file; for that i am using the following command :
FILE_LINE_COUNT=`wc -l $INT_IN/$RAW_FILE_NAME`
if i do an echo on FILE_LINE_COUNT then i get
241 /home/data/testfile.txt
I don't want the directory path to be displayed. Variable... (1 Reply)
I have a file with a list of config files numbered on the lefthand side 1-300. I need to have bash read each lines number and assign it to a variable so it can be chosen by the user called by the script later.
Ex. 1 some data
2 something else
3 more stuff
which number do you... (1 Reply)
Hiii
I am very new to shell scripting.This is my data file
a.txt:
56
45.78
1000
11.23
76.89
45
34.56
23
3400
100
..........
Now i am must use shell scripting to read n number of lines from the file & from ts n number of lines i need to find greatest number among them & so on for... (44 Replies)
a. How do I display the content of the file containing what Ive merged using a filter which would display only the lines of the file which don't contain number, for example 3 or 6. (3 Replies)
How can I find the number of lines in a file excluding lines
starting with #? (4 Replies)
Discussion started by: kristinu
4 Replies
LEARN ABOUT X11R4
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)
12-30-2015
Number of Lines in a file
