Hi,
I am trying to extracting the sum of all varibles listed in a file.
The code is as follows
##### FILE1 ########
Value1:2
Value2:2
Value3:6
Value4:5
##### shell script ######
#!/bin/sh
total=0 (2 Replies)
Hi,consider this fields,
$1 $2 $3
981 0 1
984 0 4
985 1 0
987 0 2
990 0 0
993 0 3
995 2 0
996 0 1
999 0 4
for each occurence of zero in column $2 and $3 I need to sum $1 fields, so for example, in this piece of code the result of $1 is 8910. I'm sure... (2 Replies)
Hi Experts,
I am adding a column of numbers with awk , however not getting correct output:
# awk '{sum+=$1} END {print sum}' datafile
2.15291e+06
How can I getthe output like : 2152910
Thank you..
# awk '{sum+=$1} END {print sum}' datafile
2.15079e+06 (3 Replies)
Hi all,
I need to sum values for fields in a delimited file as below:
2010-03-05|||
2010-03-05|||123
2010-03-05|467.621|369.532|
2010-03-06|||
2010-03-06||2|
2010-03-06|||444
2010-03-07|||
2010-03-07|||
2010-03-07|655.456|1019.301|
Code used is:
nawk -F "|" ' { sum +=... (7 Replies)
Hi,
I am unable sum of each column in the loop usng awk command.
Awk is not allowing the parameters in the command.
i am facing the below error.
awk: 0602-562 Field $() is not correct.
Source file
abc.txt
100,200,300,400,500,600,700,800,900
101,201,301,401,501,601,701,801,901
... (1 Reply)
Hi,
I have a file with header, detail and trailer records.
HDR|111
DTL|abc|100|xyz
DTL|abc|50|xyz
TRL|150
I need to add the values in 3rd field from DTL records.
Using awk, I am doing it as follows:
awk -F'|' '$1=="DTL"{a += $3} END {print a}' <source_file>
However, I want to... (3 Replies)
Hi
i have to calculate some numbers, column by column.
Herfore i used a for-loop..
for i in {4..26};do awk -F"," '{x'$i'+=$'$i'}END{print '$i'"\t" x'$i'}' file.tmp;done
----- printout -----
4 660905240
5 71205272
6 8.26169e+07
7 8.85961e+07
8 8.60936e+07
9 7.42238e+07
10 5.6051e+07... (7 Replies)
Hi all,
I have one host i need to run in loop to check the capacity from different frame and get the output to one file and sum it and convert to TB
this is Code
#!/bin/ksh
DATE=`date '+%d%m%y'`
for f in `cat /home/esx-capacity/esx-host.txt`
do
for g in `cat /home/esx-capacity/frame`... (10 Replies)
Discussion started by: ranjancom2000
10 Replies
LEARN ABOUT CENTOS
clp
CLP(1) General Commands Manual CLP(1)NAME
clp - linear program solver
SYNOPSIS
clp filename [ options ] solutionfile
DESCRIPTION
This manual page documents briefly the clp command.
clp -- interface to the coin linear programming solver. clp solves the following linear optimization program:
minimize c^t x
such that: row_lb <= Ax <= row_ub
column_lb <= x <= column_ub
OPTIONS
When no options are given clp enters the interactive command line mode. Otherwise the program enters a batch mode, for which a summary of
options is included below. For a complete description, see /usr/share/doc/coinor-libclp-doc.
-help Show summary of options.
-primalsimplex
solve the problem using the primal simplex method
-dualsimplex
solve the problem using the dual simplex method
-maximize
maximize the problem
SEE ALSO glpsol(1),dsdp5(1)
This program is fully documented in the accompanying html documentation which can be found in /usr/share/doc/coinor-libclp-doc if the
coinor-libclp-doc package is installed.
AUTHOR
clp was written by John J. Forrest <jjforre@us.ibm.com> et.al.
This manual page was written by Soeren Sonnenburg <sonne@debian.org>, for the Debian project (but may be used by others).
May 7, 2008 CLP(1)