It would help if you showed us what output you had hoped to produce with your changes to the code I suggested. And, I'm not sure that I understand why you're getting the diagnostic that you showed us. (I don't think I've ever seen awk complain about line 0 in an input file, I don't see anything in your code where the string d is immediately followed by an open parenthesis, and I thought AIX utilities always included an error number in diagnostic messages.) But, making some guesses and assuming that you want to print the string specified by the parameter passed to your shell script as the first field in the output (instead of the 1st line in the 1st input file), you might get what you want by making the following three changes to your script:

1. Delete:

Code:

G=$1

2. Change:

Code:

awk '

to:

Code:

awk -v G="$1" '

3. And change:

Code:

print "$G", d[1, i] in d ? d[1,i] : "NA", (2, i) in d ? d[2,i] : "NA",

to:

Code:

print G, (1, i) in d ? d[1,i] : "NA", (2, i) in d ? d[2,i] : "NA",

Then try running your modified script and see if that does what you want.

Your reference to $G inside the awk script doesn't work because shell variables are not expanded inside the single quotes surrounding your awk script, double quoting a string in an awk program make the enclosed string literal, and $G in an awk program expands to the contents of the field number specified by the contents of the awk variable named G (not to the contents of the shell variable named G from the shell script that invoked awk.