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Top Forums Shell Programming and Scripting sed Range Pattern and 2 lines before Start Pattern Post 302960206 by Don Cragun on Thursday 12th of November 2015 04:47:43 AM
Old 11-12-2015
With sed -n, nothing is printed unless you explicitly ask for it to be printed. Because you didn't anchor the search for Srt to the start of a line and the two lines before the line that just contains the string Srt also contain the string Srtin both cases, your sed command produces the output you want if you add a p flag to the command you showed us:
Code:
sed -n '/Srt/,/End/p' filename

Does it have to be sed? If the lines before the line just containing:
Code:
Srt

can contain arbitrary text not including Srt, this is easier with ed or ex:
Code:
ed -s filename <<-END
	g/^Srt$/.-2,/^End$/p
	q
END

 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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