Hello all,
I have a weird issue when trying to substitute the slashes into backslashes.
If I execute this on the command-line (bash / ksh) I get the path correctly translated with backslashes instead of slashes.
> echo $PWD | sed 's/\//\\/g'
However, when I put this in my script to... (3 Replies)
Hi Friends,
Can any of you explain me about the below line of code?
mn_code=`env|grep "..mn"|awk -F"=" '{print $2}'`
Im not able to understand, what exactly it is doing :confused:
Any help would be useful for me.
Lokesha (4 Replies)
Hello experts,
I know line number of the word I want to replace. Can "sed" substitute word on a specific line?
As well, can sed substitute words inside a specific patten.
ex. <word>lalala</word> #replace anything between <word> and </word>
minifish (2 Replies)
Hey all,
I am trying to disable a certain cronjob before I run a backup. I want to be able to add/remove a "#" from the beginning on the crontab line it is located on.
Here is the crontab:
46 11 * * * /etc/webmin/cron/tempdelete.pl
@daily /etc/webmin/time/sync.pl
*/5 * * * *... (4 Replies)
Hi,
I have line in input file as below:
3G_CENTRAL;INDONESIA_(M)_TELKOMSEL;SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL
My expected output for line in the file must be :
"1-Radon1-cMOC_deg"|"LDIndex"|"3G_CENTRAL|INDONESIA_(M)_TELKOMSEL"|LAST|"SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL"
Can someone... (7 Replies)
logs:
"/home/abc/public_html/index.php"
"/home/abc/public_html/index.php"
"/home/xyz/public_html/index.php"
"/home/xyz/public_html/index.php"
"/home/xyz/public_html/index.php"
how to use "cut" or "awk" or "sed" to get the following result:
abc
abc
xyz
xyz
xyz (8 Replies)
Hello.
System : opensuse leap 42.3
I have a bash script that build a text file.
I would like the last command doing :
print_cmd -o page-left=43 -o page-right=22 -o page-top=28 -o page-bottom=43 -o font=LatinModernMono12:regular:9 some_file.txt
where :
print_cmd ::= some printing... (1 Reply)
SUSE linux
bash shell
this works
test -d /tmpp && echo "directory exists" || echo "directory doesn't exists" |sed -e "s/^/prefix /"
prefix directory doesn't exists
but why doesn't this work?
test -d /tmp && echo "directory exists" || echo "directory doesn't exists" |sed -e... (3 Replies)
Discussion started by: snoman1
3 Replies
LEARN ABOUT CENTOS
do
DO(7) PostgreSQL 9.2.7 Documentation DO(7)NAME
DO - execute an anonymous code block
SYNOPSIS
DO [ LANGUAGE lang_name ] code
DESCRIPTION
DO executes an anonymous code block, or in other words a transient anonymous function in a procedural language.
The code block is treated as though it were the body of a function with no parameters, returning void. It is parsed and executed a single
time.
The optional LANGUAGE clause can be written either before or after the code block.
PARAMETERS
code
The procedural language code to be executed. This must be specified as a string literal, just as in CREATE FUNCTION. Use of a
dollar-quoted literal is recommended.
lang_name
The name of the procedural language the code is written in. If omitted, the default is plpgsql.
NOTES
The procedural language to be used must already have been installed into the current database by means of CREATE LANGUAGE. plpgsql is
installed by default, but other languages are not.
The user must have USAGE privilege for the procedural language, or must be a superuser if the language is untrusted. This is the same
privilege requirement as for creating a function in the language.
EXAMPLES
Grant all privileges on all views in schema public to role webuser:
DO $$DECLARE r record;
BEGIN
FOR r IN SELECT table_schema, table_name FROM information_schema.tables
WHERE table_type = 'VIEW' AND table_schema = 'public'
LOOP
EXECUTE 'GRANT ALL ON ' || quote_ident(r.table_schema) || '.' || quote_ident(r.table_name) || ' TO webuser';
END LOOP;
END$$;
COMPATIBILITY
There is no DO statement in the SQL standard.
SEE ALSO
CREATE LANGUAGE (CREATE_LANGUAGE(7))
PostgreSQL 9.2.7 2014-02-17 DO(7)