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Top Forums Shell Programming and Scripting Find Data in test file and write each out to a line Post 302958814 by Don Cragun on Monday 26th of October 2015 03:54:54 PM
Old 10-26-2015
You can't get an exit code of -1 from a process run by the shell.

Your comments about the format of center.txt described in your comments and the format of center.txt implied by the comments in your code do not match.

The output format you said you wanted and the echo statements in your code do not match. I don't think the echo statements in the code below are correct either, but I hope they are close.

And having two nested loops reading from the same file can't work.

Perhaps the following will come closer to what you want???
Code:
#!/bin/bash
# set initial variables
# ask for the input filename from Zenity
file="$(zenity --file-selection --title="Select a Wardells Input File")"
case $? in
(0)	echo "\"$file\" selected.";;
(1)	echo "No file selected."
	exit 1;;
(*)	echo "An unexpected error has occurred."
	exit 2;;
sac

IFS=","
name=${file%.*}	# finds the Name part of the input filename
fileevt="$name.evt"	# Output filename for event listing
outfile="$name.txt"	# Output filenme

echo "the input file name to use will be $file"
echo $name
echo $outfile

mmcodes=1		# have MM codes been done?  Not used in this script...

rm -f "$outfile"	# Delete Output file

#**********************************************************************
#Main Program code
#**********************************************************************
#extract event numbers from line
while read A cname B athnum firstname lastname gender age REST
do	echo "Name = $firstname"
	echo "Surname = $lastname"
	# read the Center Name and ShortName from  External file.  format is:
	#	CenterName,CenterShortName,CenterNumber
	read X csname centnum < <(grep "^${cname}," centers.txt)

	for event in $REST
	do	[ ! "$event" ] && continue
		echo "D;$lastname;$firstname;;$gender;$cname;;$csname;$centnum;$age;;$event;;M;1;$athnum;;;;"      
		echo "D;$lastname;$firstname;;$gender;$cname;;$csname;$centnum;$age;;$event;;M;1;$athnum;;;;" >> "$outfile"
	done
done < "$file"		# specify the import file to work on

This User Gave Thanks to Don Cragun For This Post:
 

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ZIPARCHIVE.OPEN(3)							 1							ZIPARCHIVE.OPEN(3)

ZipArchive::open - Open a ZIP file archive

SYNOPSIS
mixed ZipArchive::open (string $filename, [int $flags]) DESCRIPTION
Opens a new zip archive for reading, writing or modifying. PARAMETERS
o $filename - The file name of the ZIP archive to open. o $flags - The mode to use to open the archive. o ZipArchive::OVERWRITE o ZipArchive::CREATE o ZipArchive::EXCL o ZipArchive::CHECKCONS RETURN VALUES
o $Error codes - Returns TRUE on success or the error code. o ZipArchive::ER_EXISTS File already exists. o ZipArchive::ER_INCONS Zip archive inconsistent. o ZipArchive::ER_INVAL Invalid argument. o ZipArchive::ER_MEMORY Malloc failure. o ZipArchive::ER_NOENT No such file. o ZipArchive::ER_NOZIP Not a zip archive. o ZipArchive::ER_OPEN Can't open file. o ZipArchive::ER_READ Read error. o ZipArchive::ER_SEEK Seek error. EXAMPLES
Example #1 Open and extract <?php $zip = new ZipArchive; $res = $zip->open('test.zip'); if ($res === TRUE) { echo 'ok'; $zip->extractTo('test'); $zip->close(); } else { echo 'failed, code:' . $res; } ?> Example #2 Create an archive <?php $zip = new ZipArchive; $res = $zip->open('test.zip', ZipArchive::CREATE); if ($res === TRUE) { $zip->addFromString('test.txt', 'file content goes here'); $zip->addFile('data.txt', 'entryname.txt'); $zip->close(); echo 'ok'; } else { echo 'failed'; } ?> PHP Documentation Group ZIPARCHIVE.OPEN(3)
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