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Top Forums Shell Programming and Scripting Find Data in test file and write each out to a line Post 302958746 by kcpoole on Monday 26th of October 2015 05:48:21 AM
Old 10-26-2015
As mentioned in the previous reply
OS = Linux, Bash Shell

Part of my existing code below which pulls my required variables out already

Code:
#**********************************************************************
#Main Proram code
#**********************************************************************

while read line 
    do
        echo $line
        echo
        cname=$(echo $line | cut -d, -f2)        # Extract Centre Short name
            IFS="," read X csname centnum < <(grep "^${cname}," centers.txt) # "read the Center Name and ShortName from  External file  eg $centnum,$cname,$csname
        athnum=$(echo $line | cut -d, -f4)          # Extract Athlete Number
        firstname=$(echo $line | cut -d, -f5)         # Extract Athlete First Name
        lastname=$(echo $line | cut -d, -f6)         # Extract Athlete Last Name
        gender=$(echo $line | cut -d, -f7)         # Extract Athlete Gender
        age=$(echo $line | cut -d, -f8)         # Extract Athlete Age    
            
#extract event numbers from line


        echo D';'$lastname';'$firstname';;'$gender';;'$csname';'$cname';'$age';;'$event';;M;1;'$athnum';;;;' >> $outfile    
    
    done <"$file"                                # specifly the import file to work on

The only bit i am having an issue with is writing the indivdual event codes in turn to a variable so I can write my output line

Thought to do something like recusively check each colun in the input file and test to see if that is valid data, and if so write out the the line. Every check would have to check for the CR to find endof line and then go to nex one

Code:
column = 9
until [ some Test for end of line ] #Test for end of line
    echo "Column to test is" $column

    do 
        event=$(echo $line | cut -d, -f$column)  # Event that athlete has entered
        echo $event
        ((column++))
    done
done

yes I know this does not work as is, but is this an efficient ( and even possible way to do it or is there some better methods?

Ken
 

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BB-CSVINFO.CGI(1)					      General Commands Manual						 BB-CSVINFO.CGI(1)

NAME
bb-csvinfo.cgi - CGI program to show host information from a CSV file SYNOPSIS
bb-csvinfo.cgi DESCRIPTION
bb-csvinfo.cgi is invoked as a CGI script via the bb-csvinfo.sh CGI wrapper. Based on the parameters it receives, it searches a comma- separated file for the matching host, and presents the information found as a table. bb-csvinfo.cgi is passed a QUERY_STRING environment variable with the following parameters: key (string to search for, typically hostname) column (columnnumber to search - default 0) db (name of the CSV database file in $BBHOME/etc/, default hostinfo.csv) delimiter (delimiter character for columns, default semi-colon) CSV files are easily created from e.g. spreadsheets, by exporting them in CSV format. You should have one host per line, with the first line containing the column headings. Despite their name, the default delimiter for CSV files is the semi-colon - if you need a different delimiter, invoke bb-csvinfo.cgi with the "delimiter=<character>" in the query string. Example usage This example shows how you can use the bb-csvinfo CGI. It assumes you have a CSV-formatted file with information about the hosts stored as $BBHOME/etc/hostinfo.csv, and the hostname is in the first column of the file. Use with the bbgen --docurl The --docurl option to bbgen(1) sets up all of the hostnames on your Xymon webpages to act as links to a CGI script. To invoke the bb-csvinfo CGI script, run bbgen with the option --docurl=/cgi-bin/bb-csvinfo.sh?db=hostinfo.csv&key=%s SEE ALSO
bb-hosts(5), hobbitserver.cfg(5), bbgen(1) Xymon Version 4.2.3: 4 Feb 2009 BB-CSVINFO.CGI(1)
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