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Full Discussion: Segmentation Fault ERROR in C
Top Forums Programming Segmentation Fault ERROR in C Post 302958137 by DinisR on Monday 19th of October 2015 07:52:49 PM
Old 10-19-2015
Thank you for your answer!

Here are my functions which weren't illustrated.

check_property

Code:
int check_property(int *vec, int iL, int iR) {
  int k, res, resl, resr;
  int iM = (iR - iL) / 2;

  if (iM == 0) {
    if (vec[iL] != vec[iR]) return(0);
    else return(1);
  }
  for (res = 1, k = 0; k < (iR-iL); k++) {
    if (vec[iL + k] != vec[iL + k + 1]) {
      res = 0;
      break;
    }
  }
  resl = check_property(vec, iL, iL + iM);
  resr = check_property(vec, iL + iM+1, iR);
  return(res+min(resl,resr));
}

check

Code:
int check(int N) {
  int K = 1;

  while (K < N) {
    K = K * 2;
    if (K == N)
      return(1);
  }
  return(0);
}

min

Code:
int min(int a, int b) {
  if (a < b) return (a);
  else return(b);
}

But i agree with your code, and it works, the s() functions works fine on
&vec[s(N, i, j)]

But i still cant understand why it doesnt works with just
&vec[i][j]

You say:
Quote:
the compiler has never been told the dimensions of that array. So, that can't work.
By inc the i an j, I'm giving the dimension of the array until it reaches its max which is N^2 or am I incorrect?

Is there a way to do it without using the s() function?


POST EDIT:

I have done a new solution, i came up with this on the memory allocation:

Code:
/* allocate memory, read in the array and print it */
  vec = (int**)malloc(N*sizeof(int*));
  if ( vec == NULL ) {
    fprintf (stderr, "ERROR: not enough memory available!\n");
    exit ( 2 );
  }
/*New allocation*/
  for (j=0; j<N; j++){
    vec[j]= (int*)malloc(N*sizeof(int));
      if ( vec[j] == NULL ) {
    fprintf (stderr, "ERROR: not enough memory available!\n");
    exit ( 4 );
    }
  }

Now i understand what you were telling me about the dimensions.
I have debated this with a friend of mine and he told me there were 2 solutions to my problem; this one of the memory allocation, or yours, creating a s() function like you did

Thank you for your time!
Last edited by DinisR; 10-19-2015 at 10:43 PM..
 

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LEARN ABOUT CENTOS

vec

vec(2rheolef)                                                       rheolef-6.1                                                      vec(2rheolef)

NAME

       vec - vector in distributed environment (rheolef-6.1)

SYNOPSYS

       STL-like vector container for a sequential or distributed memory machine model.  Additional operation fom classical algebra.

EXAMPLE

       A sample usage of the class is:

            int main(int argc, char**argv) {
               environment distributed(argc, argv);
               vec<double> x(100, 3.14);
               dout << x << endl;
            }

IMPLEMENTATION NOTE

       Implementation use array<T,M>.

IMPLEMENTATION

       template <class T, class M = rheo_default_memory_model>
       class vec : public array<T, M> {
       public:

       // typedef:

           typedef array<T, M> base;
           typedef typename base::size_type                         size_type;
           typedef std::ptrdiff_t                                   difference_type;
       #ifdef TODO
           // pb compile avec boost sur foehn:
           typedef typename base::difference_type                   difference_type;
       #endif // TODO
           typedef basic_range<size_type, difference_type>          range_type;
           typedef typename base::reference                         reference;
           typedef typename base::const_reference                   const_reference;
           typedef typename base::iterator                          iterator;
           typedef typename base::const_iterator                    const_iterator;

       // allocator/deallocator:

           vec (const distributor& ownership,
               const T&  init_val = std::numeric_limits<T>::max());

           vec(size_type dis_size = 0,
               const T&  init_val = std::numeric_limits<T>::max());

           void resize (
               const distributor& ownership,
               const T&  init_val = std::numeric_limits<T>::max());

           void resize (
               size_type size = 0,
               const T&  init_val = std::numeric_limits<T>::max());

       // accessors:

           const_reference operator[] (size_type i) const;
           reference       operator[] (size_type i);

           T max_abs () const;

       // range:

           vec(const vec_range<T,M>& vr);
           vec(const vec_range_const<T,M>& vr);
           vec<T,M>& operator= (const vec_range<T,M>& vr);
           vec<T,M>& operator= (const vec_range_const<T,M>& vr);

           vec_range_const<T,M> operator[] (const range_type& r) const;
           vec_range<T,M>       operator[] (const range_type& r);

       // assignment to a constant:

           vec<T,M>& operator= (const int& expr);
           vec<T,M>& operator= (const T& expr);

       // expression template:

           template<typename Expr>
           vec (const Expr& expr);

           template<typename Expr>
           vec<T,M>& operator= (const vec_expr<Expr>& expr);

           template<typename Expr>
           vec<T,M>& operator+= (const Expr& expr);

           template<typename Expr>
           vec<T,M>& operator-= (const Expr& expr);

       // initializer list (c++ 2011):

       #ifdef _RHEOLEF_HAVE_STD_INITIALIZER_LIST
           vec (const std::initializer_list<vec_concat_value<T,M> >& init_list);
           vec<T,M>& operator= (const std::initializer_list<vec_concat_value<T,M> >& init_list);
       #endif // _RHEOLEF_HAVE_STD_INITIALIZER_LIST
       };

rheolef-6.1                                                         rheolef-6.1                                                      vec(2rheolef)
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