Removing a character at specific position in a column
Hi,
I have a file like this (about 8 columns in total, this being the 2nd column)
I want to remove the _ at the end of the line.
And at later stages I would want to replace the _ with another character perhaps.
Hi,
I need to add Pipe (|) at 5th and 18th position of all records a file. How can I do this?
I tried to add it at 5th position using the below code. It didnt work. Please help!!!
awk '{substr($0,5,1) ~ /|/}{print}' $input_file > $temp_file (1 Reply)
I am trying to use sed to replace specific characters at a specific position in the file with a different value... can this be done?
Example:
File:
A0199999123
A0199999124
A0199999125
Need to replace 99999 in positions 3-7 with 88888.
Any help is appreciated. (5 Replies)
I have a file that I need to parse using a script. The dates in the file are displayed in the format:
Mar 2, 2011 9:09:31 PM
I have tried using the date command %e and %l but it pads an extra space for the day and hour if they are single digits.
So this I used a normal date command:
... (6 Replies)
Hi, im still new in unix.
i want to ask how to delete character on specific position in line, lets say i want to remove 5 character from position 1000, so characters from position 1000-1005 will be deleted.
i found this sed command can delete 4 characters from position 10, but i dont know if... (7 Replies)
Discussion started by: bluesue
7 Replies
9. Post Here to Contact Site Administrators and Moderators
In file, we have millions of records each of 1000 in length. And at specific position say 800 there is a space, we need to replace it with Character X if the ID in that row starts with 123.
So far i have used the below which is replacing space at that position to X but its not checking for... (3 Replies)
I will appreciate if you help me here in this script in Solaris Enviroment.
Scenario:
i have 2 files :
1) /tmp/TRANSACTIONS_DAILY_20180730.txt:
201807300000000004
201807300000000005
201807300000000006
201807300000000007
201807300000000008
2)... (10 Replies)
Discussion started by: teokon90
10 Replies
LEARN ABOUT DEBIAN
neaten
NEATEN(1) General Commands Manual NEATEN(1)NAME
neaten - neaten up output columns
SYNOPSIS
neaten [ format ]
DESCRIPTION
Neaten reads from its standard input and neatens up columns separated by white space using the specified format. The format is a string
consisting of a positive integer followed by an alignment character and another integer. The alignment character is usually a decimal
point ('.'), but it can be any non-digit.
The alignment character is used as the central point of each column. The total column field width will be the number to the left of the
alignment character plus one for the alignment character itself plus the number to the right of the alignment character.
If a field does not contain the alignment character, it will be printed to the left of where the alignment character would have appeared.
If a field is too long to print within the specified format, the entire field will be printed and that row will not be aligned with the
rest.
The default format is "8.8".
EXAMPLE
To examine a file with columns of numbers:
neaten 10.8 < input | more
BUGS
Columns wider than the total width of the format specification will be printed without any separating white space.
The program does not do anything special with tabs on the input.
AUTHOR
Greg Ward
SEE ALSO cnt(1), rcalc(1), rlam(1), total(1)RADIANCE 11/15/93 NEATEN(1)