Login or Register to Ask a Question and Join Our Community

Sponsored Content
Full Discussion: Split 1 column into numerous columns based on patterns
Top Forums UNIX for Dummies Questions & Answers Split 1 column into numerous columns based on patterns Post 302957535 by RudiC on Monday 12th of October 2015 02:02:39 PM
Old 10-12-2015
Try also
Code:
awk '
BEGIN           {SRCH="NEW (PRODUCT|ITEM), VERSION 1.1"
                }
$0 ~ SRCH       {if (RES) print ORS RES
                 RES = ""
                 print
                 getline
                 print
                }
/^FIELD/        {printf "%s\t", $1
                 getline
                 RES = RES $0 "\t"
                }
END             {print ORS RES
                }
' file
"NEW PRODUCT, VERSION 1.1"
PRODUCT_01
FIELD_X    FIELD_Y    
11.11      22.22    
"NEW ITEM, VERSION 1.1"
PRODUCT_02
FIELD_X    FIELD_Y    FIELD_Z    
33.33      44.44      55.55

 

10 More Discussions You Might Find Interesting

1. Web Development

split the fields in a column into 3 columns

Have a column "address" which is combination of city, region and postal code like. Format is : city<comma><space>region<space>postal code abc, xyz 123456 All these three city, region and postal code are not mandatory. There can be any one of the above. In that case a nell... (2 Replies)
Discussion started by: rakshit
2 Replies

2. UNIX for Dummies Questions & Answers

split one column into multiple columns

hey guys... Im looking to do the following: 1 2 3 4 5 6 7 8 9 Change to: 1 4 7 2 5 8 3 6 9 Did use | perl -lpe'$\=$.%3?$":"\n"' , but it doesnt give me the matrix i want. (3 Replies)
Discussion started by: zaneded
3 Replies

3. Shell Programming and Scripting

split one column into multiple columns

hey, i have the following data: 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 0.000000 (7 Replies)
Discussion started by: zaneded
7 Replies

4. Shell Programming and Scripting

Split into columns based on the parameter and use & as delimiter

Here is my source, i have million lines like this on a file. disp0201.php?poc=4060&roc=1&ps=R&ooc=13&mjv=6&mov=5&rel=5&bod=155&oxi=2&omj=5&ozn=1&dav=20&cd=&daz=& drc=&mo=&sid=&lang=EN&loc=JPN I want to split this into columns in order to load in database, anything starts with"&mjv=6" as first... (13 Replies)
Discussion started by: elamurugu
13 Replies

5. Shell Programming and Scripting

Split the file based on column

Hi, I have a file sample_1.txt (300k rows) which has data like below: * Also each record is around 64k bytes 11|1|abc|102553|125589|64k bytes of data 10|2|def|123452|123356|...... 13|2|geh|144351|121123|... 25|4|fgh|165250|118890|.. 14|1|abc|186149|116657|......... (6 Replies)
Discussion started by: sol_nov
6 Replies

6. UNIX for Dummies Questions & Answers

Split file based on column

i have file1.txt asdas|csada|130310|0423|A1|canberra sdasd|sfdsf|130426|2328|A1|sydney Expected output : on eaceh third and fourth colum, split into each two characters asdas|csada|13|03|10|04|23|A1|canberra sdasd|sfdsf|13|04|26|23|28|A1|sydney (10 Replies)
Discussion started by: radius
10 Replies

7. Shell Programming and Scripting

awk to sum a column based on duplicate strings in another column and show split totals

Hi, I have a similar input format- A_1 2 B_0 4 A_1 1 B_2 5 A_4 1 and looking to print in this output format with headers. can you suggest in awk?awk because i am doing some pattern matching from parent file to print column 1 of my input using awk already.Thanks! letter number_of_letters... (5 Replies)
Discussion started by: prashob123
5 Replies

8. UNIX for Dummies Questions & Answers

File merging based on column patterns

Hello :) I am in this situation: Input: two tab-delimited files, `File1` and `File2`. `File2` (`$2`) has to be parsed by patterns found in `File1` (`$1`). Expected output: tab-delimited file, `File3`. `File3` has to contain the same rows as `File2`, plus the corresponding value in... (5 Replies)
Discussion started by: dovah
5 Replies

9. UNIX for Beginners Questions & Answers

How to split a column based on |?

Hi all, Newbie here, so please bear over with my stupid question :) I have used far too long time today on figuring this out, so I hope that someone here can help me move on. I have some annotation data for a transcriptome where I want to split a column containing NCBI accession IDs into a... (7 Replies)
Discussion started by: BioBing
7 Replies

10. UNIX for Beginners Questions & Answers

Using awk to split a column into two columns

Hi, I am trying to split the following output into two columns, where each column has Source: Destination: OUTPUT TO FILTER $ tshark -r Capture_without_mtr.pcap -V | awk '/ (Source|Destination): /' | more Source: x.x.x.x Destination: x.x.x.x Source:... (2 Replies)
Discussion started by: sand1234
2 Replies

LEARN ABOUT CENTOS

sla_lin_berr.f

sla_lin_berr.f(3)						      LAPACK							 sla_lin_berr.f(3)

NAME

       sla_lin_berr.f -

SYNOPSIS

   Functions/Subroutines
       subroutine sla_lin_berr (N, NZ, NRHS, RES, AYB, BERR)
	   SLA_LIN_BERR computes a component-wise relative backward error.

Function/Subroutine Documentation
   subroutine sla_lin_berr (integerN, integerNZ, integerNRHS, real, dimension( n, nrhs )RES, real, dimension( n, nrhs )AYB, real, dimension( nrhs
       )BERR)
       SLA_LIN_BERR computes a component-wise relative backward error.

       Purpose:

	       SLA_LIN_BERR computes componentwise relative backward error from
	       the formula
		   max(i) ( abs(R(i)) / ( abs(op(A_s))*abs(Y) + abs(B_s) )(i) )
	       where abs(Z) is the componentwise absolute value of the matrix
	       or vector Z.

       Parameters:
	   N

		     N is INTEGER
		The number of linear equations, i.e., the order of the
		matrix A.  N >= 0.

	   NZ

		     NZ is INTEGER
		We add (NZ+1)*SLAMCH( 'Safe minimum' ) to R(i) in the numerator to
		guard against spuriously zero residuals. Default value is N.

	   NRHS

		     NRHS is INTEGER
		The number of right hand sides, i.e., the number of columns
		of the matrices AYB, RES, and BERR.  NRHS >= 0.

	   RES

		     RES is REAL array, dimension (N,NRHS)
		The residual matrix, i.e., the matrix R in the relative backward
		error formula above.

	   AYB

		     AYB is REAL array, dimension (N, NRHS)
		The denominator in the relative backward error formula above, i.e.,
		the matrix abs(op(A_s))*abs(Y) + abs(B_s). The matrices A, Y, and B
		are from iterative refinement (see sla_gerfsx_extended.f).

	   BERR

		     BERR is REAL array, dimension (NRHS)
		The componentwise relative backward error from the formula above.

       Author:
	   Univ. of Tennessee

	   Univ. of California Berkeley

	   Univ. of Colorado Denver

	   NAG Ltd.

       Date:
	   September 2012

       Definition at line 102 of file sla_lin_berr.f.

Author
       Generated automatically by Doxygen for LAPACK from the source code.

Version 3.4.2							  Tue Sep 25 2012						 sla_lin_berr.f(3)
All times are GMT -4. The time now is 11:38 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy