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Top Forums Shell Programming and Scripting sed -- Find pattern -- print remainder -- plus lines up to pattern -- Minus pattern Post 302957424 by Klasform on Saturday 10th of October 2015 02:41:39 PM
Old 10-10-2015
Code:
sed -n '/.*oy\/size">\(.*\).*$/ {s//\1/; :L; N;

So what your saying is:

Pattern space is going to have
1: PDF converters
2: ....the whole complete line
Code:
s//\1/;

takes only the first line from pattern space, which is, 1:
and gets printed, released somewhere around, hmmm, not sure where on that line, anymore!

The rest I think I get Smilie

Ok hope it makes sense.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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