Sponsored Content
Top Forums Shell Programming and Scripting Pass date (YYYY-MM-DD) as parameter and get Day Post 302956614 by ashwin3086 on Thursday 1st of October 2015 10:48:39 AM
Old 10-01-2015
Thanks balajesuri.

It works perfectly. I did go through the usage of POSIX/ strftime to understand why you have used -1 for $y[1] (Month) and was able to get the answer.

Thanks again for your help. Smilie
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Change Date from dd-mmm-yyyy to mm/dd/yyyy

I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
Discussion started by: stringzz
9 Replies

2. Shell Programming and Scripting

converting the date field from dd/mm/yyyy to yyyy/mm/dd

How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix my script will generate text file which have two fields one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
Discussion started by: pareshan
4 Replies

3. Shell Programming and Scripting

Function to get day of week from YYYY-MM-DD date

Can't find out how to get the day of the week from a given date, anyone got a code snippet that could help please? Ta!! (4 Replies)
Discussion started by: couponmeup
4 Replies

4. Shell Programming and Scripting

change date format from yyyy/mm/dd to dd/mm/yyyy

(Attention: Green PHP newbie !) I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
Discussion started by: keyboarder
6 Replies

5. Shell Programming and Scripting

get system date, format it, pass it as a parameter to a perl script - all in cron job

I am trying to get the string containing date - in a specfic format actually, although I think that part is inconsequencial - 1110226^1110226^1110226^1110226^1110226 - through echo or printf or in some other way - created within a cront job and passed as a parameter to a perl script. Now, I know... (3 Replies)
Discussion started by: v8625
3 Replies

6. Shell Programming and Scripting

Converting date DD MM YYYY to DD MON YYYY

Hello, I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10) To extract the dates, I am using shell substrings, i.e.: read line ... (4 Replies)
Discussion started by: Adamm
4 Replies

7. Shell Programming and Scripting

Day of year to dd.mm.yyyy format

Hi, How can I convert day of year value in format(yy,doy) to normal formatted (dd.mm.yyyy) string also all of them with awk or awk system function? in_file.txt --------- 12,043 12,044 12,045 12,046 out_file.txt ---------- 12.02.2012 13.02.2012 14.02.2012 15.02.2012 imagine... (5 Replies)
Discussion started by: kocaturk
5 Replies

8. Shell Programming and Scripting

Date conversion help from dd/mm/yyyy to dd/Mon/yyyy i.e. 28/10/2012 to 28/Oct/2012

Hi I have a problem with Date format in my code. 1st I am trying to convert today's date to yesterday's using YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'` And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
Discussion started by: nithinankam
3 Replies

9. UNIX for Dummies Questions & Answers

Epoch date to YYYY/MM/DD or MM/DD/YYYY

I've seen a lot of posts on this and have tried the following: echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";' But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY. I am using bash and don't know... (4 Replies)
Discussion started by: newbie2010
4 Replies

10. Shell Programming and Scripting

Date format YYYY/MM/DD to DD/MM/YYYY

I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY. When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD file... (3 Replies)
Discussion started by: Roozo
3 Replies
eXosip2 request outside of dialog(3)				    libeXosip2				      eXosip2 request outside of dialog(3)

NAME
eXosip2 request outside of dialog - Functions int eXosip_message_build_request (osip_message_t **message, const char *method, const char *to, const char *from, const char *route) int eXosip_message_send_request (osip_message_t *message) int eXosip_message_build_answer (int tid, int status, osip_message_t **answer) int eXosip_message_send_answer (int tid, int status, osip_message_t *answer) Detailed Description Function Documentation int eXosip_message_build_request (osip_message_t **message, const char *method, const char *to, const char *from, const char *route) Build a default request message. This method will be updated to send any message outside of dialog In this later case, you'll specify the method to use in the second argument. Parameters: message Pointer for the SIP request to build. method request method. (like 'MESSAGE' or 'PING'...) to SIP url for callee. from SIP url for caller. route Route header for request. (optional) int eXosip_message_send_request (osip_message_t *message) Send an request. Parameters: message SIP request to send. int eXosip_message_build_answer (inttid, intstatus, osip_message_t **answer) Build answer for a request. Parameters: tid id of transaction. status status for SIP answer to build. answer The SIP answer to build. int eXosip_message_send_answer (inttid, intstatus, osip_message_t *answer) Send answer for a request. Parameters: tid id of transaction. status status for SIP answer to send. answer The SIP answer to send. (default will be sent if NULL) Author Generated automatically by Doxygen for libeXosip2 from the source code. Version 3.1.0 Sun Jun 24 2012 eXosip2 request outside of dialog(3)
All times are GMT -4. The time now is 10:44 AM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy