I want to change a date from format dd-mmm-yyyy to mm/dd/yyyy. Is there a way to do this with sed or do you have to write a case statement to convert JAN to 01? Thanks (9 Replies)
How to convert the date field from dd/mm/yyyy to yyyy/mm/dd in unix
my script will generate text file which have two fields
one is date and another is name of the server for example this is sample date which I have to sort based on older to newer date the problem is when I found out sort will... (4 Replies)
(Attention: Green PHP newbie !)
I have an online inquiry form, delivering a date in the form yyyy/mm/dd to my feedback form. If the content passes several checks, the form sends an e-mail to me. All works fine. I just would like to receive the date in the form dd/mm/yyyy. I tried with some code,... (6 Replies)
I am trying to get the string containing date - in a specfic format actually, although I think that part is inconsequencial - 1110226^1110226^1110226^1110226^1110226 - through echo or printf or in some other way - created within a cront job and passed as a parameter to a perl script.
Now, I know... (3 Replies)
Hello,
I am writing a script that parses different logs and produces one. In the source files, the date is in DD MM YYYY HH24:MI:SS format. In the output, it should be in DD MON YYY HH24:MI:SS (ie 25 Jan 2010 16:10:10)
To extract the dates, I am using shell substrings, i.e.:
read line
... (4 Replies)
Hi,
How can I convert day of year value in format(yy,doy) to normal formatted (dd.mm.yyyy) string also all of them with awk or awk system function?
in_file.txt
---------
12,043
12,044
12,045
12,046
out_file.txt
----------
12.02.2012
13.02.2012
14.02.2012
15.02.2012
imagine... (5 Replies)
Hi I have a problem with Date format in my code.
1st I am trying to convert today's date to yesterday's using
YESTERDAY3=`perl -e '@y=localtime(time()-86400); printf "%04d/%02d/%02d",$y+1900,$y+1,$y;$y;'`
And once it is done I am trying to using the yesterday date in a grep command to... (3 Replies)
I've seen a lot of posts on this and have tried the following:
echo 1257000000| perl -e '($d,$m,$y)=(localtime(time-86400));$m+=1;$y+=1900;printf "$y/$m/$d\n";'
But I am unable to convert a past Epoch date into a format such as YYYY/MM/DD or MM/DD/YYYY.
I am using bash and don't know... (4 Replies)
I am getting output of YYYY-MM-DD and want to change this to DD/MM/YYYY.
When am running the query in 'Todd' to_date(column_name,'DD/MM/YYYY') am getting the required o/p of DD/MM/YYYY, But when am executing the same query(Netezza) in linux server(bash) am getting the output of YYYY-MM-DD
file... (3 Replies)
Discussion started by: Roozo
3 Replies
LEARN ABOUT DEBIAN
io::async::signal
IO::Async::Signal(3pm) User Contributed Perl Documentation IO::Async::Signal(3pm)NAME
"IO::Async::Signal" - event callback on receipt of a POSIX signal
SYNOPSIS
use IO::Async::Signal;
use IO::Async::Loop;
my $loop = IO::Async::Loop->new;
my $signal = IO::Async::Signal->new(
name => "HUP",
on_receipt => sub {
print "I caught SIGHUP
";
},
);
$loop->add( $signal );
$loop->run;
DESCRIPTION
This subclass of IO::Async::Notifier invokes its callback when a particular POSIX signal is received.
Multiple objects can be added to a "Loop" that all watch for the same signal. The callback functions will all be invoked, in no particular
order.
EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters:
on_receipt
Invoked when the signal is received.
PARAMETERS
The following named parameters may be passed to "new" or "configure":
name => STRING
The name of the signal to watch. This should be a bare name like "TERM". Can only be given at construction time.
on_receipt => CODE
CODE reference for the "on_receipt" event.
Once constructed, the "Signal" will need to be added to the "Loop" before it will work.
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2012-10-24 IO::Async::Signal(3pm)