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Full Discussion: Alert when files change
Top Forums Shell Programming and Scripting Alert when files change Post 302956173 by zaxxon on Monday 28th of September 2015 03:58:39 AM
Old 09-28-2015
What about posting these errors using code tags?

Flying over your code, this for a start:

Code:
"$MONITORDIR" > /opt/log.xlsx

This does nothing. It is missing an echo in front of it.

Code:
md5sum "$(FILE)" cut -d .....

There is no pipe after the md5sum command to hand it's output over to stdin of cut

Code:
NOW='date + %d%B%Y%H%M%S '

This will not be evaluated. Either use backticks or $(date ...).
There is more of those in your code.

Code:
if [-s "$(FILE); ...

There is missing a blank between the square bracket and the following arguments.
There is more of those in your code as well.

Code:
case "$prev" in 
    0) echo "'date' $FILE appeared."
...

Blocks inside case/esac have to be terminated by ;;.

And there are more and more errors.

I wonder how you can write a script as it seems you have not even tested a single line of it before putting it together.
 

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EVAL(3) 								 1								   EVAL(3)

eval - Evaluate a string as PHP code

SYNOPSIS
mixed eval (string $code) DESCRIPTION
Evaluates the given $code as PHP. Caution The eval(3) language construct is very dangerous because it allows execution of arbitrary PHP code. Its use thus is discouraged. If you have carefully verified that there is no other option than to use this construct, pay special attention not to pass any user provided data into it without properly validating it beforehand. PARAMETERS
o $code - Valid PHP code to be evaluated. The code mustn't be wrapped in opening and closing PHP tags, i.e. 'echo "Hi!";' must be passed instead of '<? echo "Hi!"; >'. It is still possible to leave and reenter PHP mode though using the appropriate PHP tags, e.g. 'echo "In PHP mode!"; ?>In HTML mode!<? echo "Back in PHP mode!";'. Apart from that the passed code must be valid PHP. This includes that all statements must be properly terminated using a semicolon. 'echo "Hi!"' for example will cause a parse error, whereas 'echo "Hi!";' will work. A return statement will immediately terminate the evaluation of the code. The code will be exe- cuted in the scope of the code calling eval(3). Thus any variables defined or changed in the eval(3) call will remain visible after it terminates. RETURN VALUES
eval(3) returns NULL unless return is called in the evaluated code, in which case the value passed to return is returned. If there is a parse error in the evaluated code, eval(3) returns FALSE and execution of the following code continues normally. It is not possible to catch a parse error in eval(3) using set_error_handler(3). EXAMPLES
Example #1 eval(3) example - simple text merge <?php $string = 'cup'; $name = 'coffee'; $str = 'This is a $string with my $name in it.'; echo $str. " "; eval("$str = "$str";"); echo $str. " "; ?> The above example will output: This is a $string with my $name in it. This is a cup with my coffee in it. NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. Tip As with anything that outputs its result directly to the browser, the output-control functions can be used to capture the output of this function, and save it in a string (for example). Note In case of a fatal error in the evaluated code, the whole script exits. SEE ALSO
call_user_func(3). PHP Documentation Group EVAL(3)
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