09-27-2015
Reply
Quote:
Originally Posted by
Don Cragun
Is this something you plan to run every 15 minutes (so you just want to see stuff added since your last run)?
Yes, I want it to run every 15 minutes and only add new events which have appeared in the last 15 minutes.
Quote:
Originally Posted by
Don Cragun
Does the log file you're examining rotate? If so, is the rotation synchronized with your script, or do you need to sometimes need to examine the end of an old log file in addition to the current log file?
Yes the log file rotates at present its approximatly once a day, when the file rotates the previous one is also gziped. The rotation isn't synced with my script as its based on volume. If we can examine the old log file in the case of rotation that would be extremely helpful.
Quote:
Originally Posted by
Don Cragun
Are you looking for the 15 minutes of data before the time on the clock when you start your script, or are you looking for the 15 minutes of data ending with the timestamp on the last entry in your log file?
15 minutes of data before the time on the clock.
Quote:
Originally Posted by
Don Cragun
What operating system and shell are you using?
GNU/Linux, shell being used is bash.
Thanks
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LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)
NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS
--debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)