09-25-2015
I don't understand.
Why is your output field separator sometimes a comma and sometimes a space and a comma? Why aren't all of the spaces removed from the output?
There is no "Pippo.com - 404 File Not Found" in your input file (in field 7 nor anywhere else). Are you just saying that you want to remove the last slash character (/) and everything that following from field 7?
Furthermore, your sample code removes the period and everything following it from the 1st field; but your desired output shows no change at all to field 1 AND your description of your problem says nothing about changing field 1.
Please be more clear in your explanation of what you are trying to do.
This User Gave Thanks to Don Cragun For This Post:
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I am trying to write a Perl script to cover a few CVS commands (setup specifically), however the VI screen that pops up and requests a comment, what is the best way of entering the text automatically (will be a variable name) and then saving that cvs notification from my Perl program?
Help is... (2 Replies)
Discussion started by: Shakey21
2 Replies
2. UNIX for Dummies Questions & Answers
Hey guys,
I am trying to setup CVS to run with an SSH connection, but am hitting a brick wall. I seem to be getting CVS to login correctly, but when I attempt to check out a module I am getting the following error:
ksh: cvs: not found
This is kinda implying to me that its not loading... (2 Replies)
Discussion started by: LiquidChild
2 Replies
3. UNIX for Advanced & Expert Users
I've experienced a problem with CVS when I've checked out sh script.
When new build was created sources were checked out from CVS under Windows. Later this build was deployed under Linux und I recieved error from shell becouse of CR-LF EOL in file. I've tryed command dos2unix and become script... (7 Replies)
Discussion started by: Hitori
7 Replies
4. Solaris
dear all
I'm one of the CVS administrators here at my company
and i have this cvs error in the messages
Sep 18 07:20:37 dev cvs: Dying gasps received from client.
can any one help me about this error .............
thanks
murad jaber (1 Reply)
Discussion started by: murad.jaber
1 Replies
5. Debian
Hi everyone...
Could one of you kind Linux experts please let me know what CVS is
In return I will kindly give you a thumbs up :b: a good trade I feel!! (1 Reply)
Discussion started by: TonyChapman
1 Replies
6. Red Hat
Hi all,
i am trying to set up a CVS server on linux and to remote access the repository using WinCVS. I am facing some problem and i am unsure whether is it the client or the server not set up properly.
In my winCVS client, i clicked Admin ->login and i specify my CVSROOT to be ":... (5 Replies)
Discussion started by: new2ss
5 Replies
7. Red Hat
Hello,
I have read a great deal of documentation on CVS and I hope I have not overlooked what I need but I have certain issues with CVS that I cannnot resolve.
The setup for the /etx/xinetd.d file I have is as follows:
# default: off
# description: The CVS service can record the history... (2 Replies)
Discussion started by: mojoman
2 Replies
8. UNIX for Dummies Questions & Answers
Currently we have a load of files which we manually edit and then commit back into CVS ready for whoever else to edit.
I have now made a script which auto-populates these files, however the powers that be still want them accessible via CVS. Is there a way I can automatically commit these files... (7 Replies)
Discussion started by: JayC89
7 Replies
9. AIX
Hello. I am using CVS on my AIX 6.1 box. I have gotten the repository setup and everything is working from command line. Now I want to use CVS on my Windows 7 machine using the remote repository on my AIX box. Has anyone else tried this? Why can't I get this to work?
I have tried using... (3 Replies)
Discussion started by: hpodhrad
3 Replies
10. Shell Programming and Scripting
Hi All,
I am just looking for CVS automation for SQL scripts. Normally Devs will check in new sql scripts or they will update the existing sql scripts with new query. We will take the scripts from CVS and run in DB. I am thinking to automate that process like whenever a new script is checked in... (1 Reply)
Discussion started by: pvmanikandan
1 Replies
LEARN ABOUT DEBIAN
plan9-join
JOIN(1) General Commands Manual JOIN(1)
NAME
join - relational database operator
SYNOPSIS
join [ options ] file1 file2
DESCRIPTION
Join forms, on the standard output, a join of the two relations specified by the lines of file1 and file2. If one of the file names is the
standard input is used.
File1 and file2 must be sorted in increasing ASCII collating sequence on the fields on which they are to be joined, normally the first in
each line.
There is one line in the output for each pair of lines in file1 and file2 that have identical join fields. The output line normally con-
sists of the common field, then the rest of the line from file1, then the rest of the line from file2.
Input fields are normally separated spaces or tabs; output fields by space. In this case, multiple separators count as one, and leading
separators are discarded.
The following options are recognized, with POSIX syntax.
-a n In addition to the normal output, produce a line for each unpairable line in file n, where n is 1 or 2.
-v n Like -a, omitting output for paired lines.
-e s Replace empty output fields by string s.
-1 m
-2 m Join on the mth field of file1 or file2.
-jn m Archaic equivalent for -n m.
-ofields
Each output line comprises the designated fields. The comma-separated field designators are either 0, meaning the join field, or
have the form n.m, where n is a file number and m is a field number. Archaic usage allows separate arguments for field designators.
-tc Use character c as the only separator (tab character) on input and output. Every appearance of c in a line is significant.
EXAMPLES
sort /etc/passwd | join -t: -1 1 -a 1 -e "" - bdays
Add birthdays to the /etc/passwd file, leaving unknown birthdays empty. The layout of /adm/users is given in passwd(5); bdays con-
tains sorted lines like
tr : ' ' </etc/passwd | sort -k 3 3 >temp
join -1 3 -2 3 -o 1.1,2.1 temp temp | awk '$1 < $2'
Print all pairs of users with identical userids.
SOURCE
/src/cmd/join.c
SEE ALSO
sort(1), comm(1), awk(1)
BUGS
With default field separation, the collating sequence is that of sort -b -ky,y; with -t, the sequence is that of sort -tx -ky,y.
One of the files must be randomly accessible.
JOIN(1)