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Full Discussion: Sending awk variables into curl in a bash script
Top Forums Shell Programming and Scripting Sending awk variables into curl in a bash script Post 302955377 by Aia on Wednesday 16th of September 2015 10:47:06 PM
Old 09-16-2015
Quote:
Originally Posted by phaethon
[...]
but it seems that the variables are not evolving gradually all together but separately
Code:
yr=`awk '{$1=substr($1, 6, 2)}1'  file1`

yr will not hold just one year, but every year for each line in file1. The same for each of your variables mo, da, ho and mi. Nonetheless, the characters extracted are off: substr($1, 6, 2) doesn't return the representation of a year.
Code:
$ awk '{$1=substr($1, 6, 2)}1' file1 
11
21
41
01

This will do:
Code:
$ awk '{$1=substr($1, 1, 4)}1' file1
2012
2012
2013
2014

Perhaps, try:
Code:
while read d; do
    yr=${d:0:4}
    mo=${d:4:2}
    da=${d:6:2}
    ho=${d:8:2}
    mi=${d:10:2}
    curl -L http://webpage/${yr}/${mo}/track${yr}${mo}${da}${ho}${mi}_infos.html
    # if yr is supposed to be yyyy
    # curl -L http://webpage/${yr}/${mo}/track${d}_infos.html
    
done < file1

If yr is supposed to be represented with only the last two digits, replace yr=${d:0:4} to yr=${d:2:2}

Of course, the whole process can be reduced to:

Code:
while read d; do
    #curl -L http://webpage/${d:0:4}/${d:4:2}/track${d}_infos.html
    # or
    #curl -L http://webpage/${d:2:2}/${d:4:2}/track${d:2}_infos.html
done < file1

Last edited by Aia; 09-17-2015 at 12:44 AM.. Reason: Add an alternative
This User Gave Thanks to Aia For This Post:
phaethon
 

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