09-16-2015
I made a stupid mistake
Thank you.
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....
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Hi All,
Calling a function with one argument and storing the return value in a shell script is as below:( so far I know)
value="`fun_1 "argument1"`"
Its working perfectly for me.
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May i please know why is it printing the script name for $0 when i pass those parameters to function.
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LEARN ABOUT REDHAT
strcpy
STRCPY(3) Linux Programmer's Manual STRCPY(3)
NAME
strcpy, strncpy - copy a string
SYNOPSIS
#include <string.h>
char *strcpy(char *dest, const char *src);
char *strncpy(char *dest, const char *src, size_t n);
DESCRIPTION
The strcpy() function copies the string pointed to by src (including the terminating ` ' character) to the array pointed to by dest. The
strings may not overlap, and the destination string dest must be large enough to receive the copy.
The strncpy() function is similar, except that not more than n bytes of src are copied. Thus, if there is no null byte among the first n
bytes of src, the result will not be null-terminated.
In the case where the length of src is less than that of n, the remainder of dest will be padded with nulls.
RETURN VALUE
The strcpy() and strncpy() functions return a pointer to the destination string dest.
BUGS
If the destination string of a strcpy() is not large enough (that is, if the programmer was stupid/lazy, and failed to check the size
before copying) then anything might happen. Overflowing fixed length strings is a favourite cracker technique.
CONFORMING TO
SVID 3, POSIX, BSD 4.3, ISO 9899
SEE ALSO
bcopy(3), memccpy(3), memcpy(3), memmove(3)
GNU
1993-04-11 STRCPY(3)