Thanks for the quick reply.

When I run this on a txt file with no duplicates it works great. But when I run it on a file with duplicates I get the following output;

Code:

 
 awk 'BEGIN { FS = OFS = "," } $2 == $3 { print f++ } END {if(f == 0) print "No Duplicates"}' List_With_Duplicates.txt

Code:

 
 0
 1

Preferred output is;

Code:

 
 a,1,1
 e,3,3

The code seems to output the iteration number of 'f' rather than the value. Is there an amendment that can be made to change this?

Thanks

Moderator's Comments:

Please use CODE tags (not ICODE tags) for multiline sample code, input, and output!

---------- Post updated at 11:41 AM ---------- Previous update was at 11:23 AM ----------

I tried;

Code:

 
 awk 'BEGIN { FS = OFS = "," } $2 == $3 { print f++ $1,$2,$3 } END {if(f == 0) print "No Duplicates"}' List_With_Duplicates.txt

And got the following output;

Code:

 
 0a,1,1
 1e,3,3

Is there a way of hiding the iteration number? When I do the same command but without the f++ the 'Non Duplicate' string is output also.

Thanks

Moderator's Comments:

Please use CODE tags (not ICODE tags) for multiline sample code, input, and output!

---------- Post updated at 11:42 AM ---------- Previous update was at 11:41 AM ----------

Sorry, was using wrong tabs