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Top Forums Shell Programming and Scripting Print all lines between two keyword if a specific pattern exist Post 302952163 by protocomm on Friday 14th of August 2015 10:48:11 AM
Old 08-14-2015
Hi !!

[QUOTE=anbu23;302952135]
Code:
$ awk ' /BEGIN/,/END/ { str = str ?  str "\n" $0 : $0 } /END/ { if( str ~ /Amit/ ) { print str }; str = "" } ' file
******** BEGIN *****
My name is Amit.
I am learning unix.
***** END *****

Could you explain the part
Code:
str = str ?  str "\n" $0

of your command line please, it's confuse for me.
I've understood that for each block /BEGIN/,/END/ you do this { str = str ? str "\n" $0 : $0 }, i know the result but it's not clear for me
Thx.
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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