The most likely cause is that you're using a 1993 version of ksh on the system where it works, but using a 1988 version of ksh or some non-ksh shell on the other system.
What is the output from the commands:
on the system where your code works.
What is the output from those same commands on the system where it doesn't work?
Hi Gurus,
I wrote a small KSH script, in that i am comparing two variables like this
curr_time = date +%h.%m
set_time=23.55
If ];
then
zip the file
fi
The above script is croned to run evey 5(3,8,.......,58) minutes, but it is zipping at 23.03 hours. My intention is at 23.58 .what... (4 Replies)
Im trying to compare two numbers with decimals but its not working as expected.
a=1
b=1.1
if
then echo "equal"
fi
When I do this it says that the numbers are equal. Ultimately Im using -le and -ge in the if statements but I tested with -eq for simplicity.
Any way to make this... (3 Replies)
Hi all,
Iīve already searched the forum but canīt find what i am doing wrong.
I am trying to compare two variables using ksh under red hat. The error I get is:
-ksh: .: MDA=`md5sum /tmp/ftp_dir_after_transfer | cut -d' ' -f1 `
MDB=`md5sum /tmp/ftp_dir_before_transfer | cut -d' ' -f1 `... (3 Replies)
hi,
i have a bash script that i want to receive a a string from another bash file. But because the string has a dot in the middle it gives me an error. The error is in this line:
let valor=$1
and the value passed is rules.txt
the error is:
let: valor=rules.txt: syntax error: invalid... (2 Replies)
For numbers between 0 and 1 the below logic is not working.
Output of above shall be "correct" but its echoing "incorrect".Kindly suggest
a=.1
if
then
echo correct
else echo incorrect
fi
Video tutorial on how to use code tags in The UNIX and Linux Forums. (3 Replies)
I am trying to perform arithmetric, for example, to increment the value of variable $a (say 3) by 0.05 but when I tried the following expression
let a=a+0.05
or a=$((a+0.05))
both returned
3.0499999999999998
I want to keep 2 decimal places so it returns 3.05 instead. (6 Replies)
i am having a varialbe a , which is input to my file
i want to multiply this input with value .43, and assign it to variable b.
i tried it as below:
#!/bin/sh
a=$1
b=`expr $1\*0.43`
echo b=$b
error : expr: non-integer argument
Please tell me , how to do this.
Thanks (10 Replies)
Hello,
I am new to shell scripting and getting the error "arithmetic syntax error" on line 55 of my script.
Below is line 55 and 56
Backup=$ (( $Year*365+$Day ))
if ] then PrevHostname=$Hostname; PrevBackup=$Backup
Error:
./mksysbChk.ksh: line 56: *365+as : arithmetic syntax... (10 Replies)
Discussion started by: hasn318
10 Replies
LEARN ABOUT OPENSOLARIS
times
times(1) User Commands times(1)NAME
times - shell built-in function to report time usages of the current shell
SYNOPSIS
sh
times
ksh
times
DESCRIPTION
sh
Print the accumulated user and system times for processes run from the shell.
ksh
Print the accumulated user and system times for the shell and for processes run from the shell.
On this man page, ksh(1) commands that are preceded by one or two * (asterisks) are treated specially in the following ways:
1. Variable assignment lists preceding the command remain in effect when the command completes.
2. I/O redirections are processed after variable assignments.
3. Errors cause a script that contains them to abort.
4. Words, following a command preceded by ** that are in the format of a variable assignment, are expanded with the same rules as a
variable assignment. This means that tilde substitution is performed after the = sign and word splitting and file name genera-
tion are not performed.
ATTRIBUTES
See attributes(5) for descriptions of the following attributes:
+-----------------------------+-----------------------------+
| ATTRIBUTE TYPE | ATTRIBUTE VALUE |
+-----------------------------+-----------------------------+
|Availability |SUNWcsu |
+-----------------------------+-----------------------------+
SEE ALSO ksh(1), sh(1), time(1), attributes(5)SunOS 5.11 15 Apr 1994 times(1)