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Top Forums Shell Programming and Scripting awk to find number in a field then print the line and the number Post 302951046 by Don Cragun on Friday 31st of July 2015 06:18:34 PM
Old 07-31-2015
Quote:
Originally Posted by MadeInGermany
Ravinder, you worked around
Code:
gsub(/[^[:digit:]]/,X,Q)

This works with the English description of the desired output, but doesn't preserve the space between strings of digits as shown in the last line of the desired output. To get the desired output, one could use:
Code:
gsub(/[^[:digit:] ]/,X,Q)

if only <space> characters are to be allowed between strings of digits, or:
Code:
gsub(/[^[:digit:][:space:]]/,X,Q)

if any combinations of <space> and <tab> characters are to be allowed (as assumed by Ravinder's following sub() statements to get rid of leading and trailing space class characters.

Note that Ravinder's suggestion to use:
Code:
                sub(/^[[:space:]]/,X,Q);
                sub(/[[:space:]]+$/,X,Q);

after getting rid of alphabetic and punctuation class characters only removes one leading whitespace character (when it seems that there could be more than one). And, both of these could be replaced by a single gsub() call:
Code:
                gsub(/^[[:space:]]+|[[:space:]]+$/,X,Q);

or, if only space characters are to be allowed between digit strings:
Code:
                gsub(/^ +| +$/,X,Q);

These 2 Users Gave Thanks to Don Cragun For This Post:
 

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