There isn't a lot of room for improvement in:
But, the comma in your print statement is adding a space to the end of the odd numbered output lines. And, as mjf said, to match the output you said you wanted; you need length>7 instead of length>=7. A slightly different way of doing it is:
but I don't know that it is any better (other than taking out the comma). The following is the best I can do using your naming conventions. It is a little bit shorter and requires fewer tests:
This User Gave Thanks to Don Cragun For This Post:
What is the more efficient way to do this (awk only and default FS) ?
$ echo "jefe@alm"|awk '{pos = index($0, "@");printf ("USER: %s\n",substr ($0,1,pos-1))}'
USER: jefe
Thx in advance (2 Replies)
Hi,
My input file is
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
..
..
I need to change the second field value from 2 to 1. i.e.,
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
..
..
Thanks in advance. (9 Replies)
Hi,
I have a long string like,
aabab|bcbcbcbbc|defgh|paswd123 dedededede|efef|ghijklmn|paswd234 ghghghghgh|ijijii|klllkkk|paswd345 lmlmlmmm|nononononn|opopopopp|paswd456
This string is devided into one space between substrings. This substrings are,
aabab|bcbcbcbbc|defgh|paswd123... (6 Replies)
Hi I am trying to run this command in ksh ...its not working
$line="123356572867116w1671716"
actual_length = 16
cut_line=`awk 'BEGIN{print substr(ARGV,1,actual_length)}' "$line"`
the substr is not giving me an output
how can i make it done
can anyone hwlp me on this
cut_line=`awk... (2 Replies)
Hi, i'm a newbie and i don't know unix...
I'm a dba oracle.
I need to cat the content of a file like this:
> ps -eaf|grep pmon
oracle 221422 1 0 Sep 17 - 7:20 ora_pmon_ORCL
oracle 405626 1 0 Sep 17 - 8:39 ora_pmon_ORCL1
oracle 491534 1 0 ... (3 Replies)
Hello life savers!!
Is there any way to use substr in awk command for returning one part of a string from declared start and stop point?
I mean I know we have this:
substr(string, start, length)
Do we have anything like possible to use in awk ? :
substr(string, start, stop)
... (9 Replies)
I have a command like this:
listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES" else if (substr ($0,37,1)==0 && NR == 3) print "NO"}'
This syntax doesn't work. But I was able to get this to work:
listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES"}'
... (4 Replies)
Hi,
- In a file test.wmi
Col1 | firstName | lastName
4003 | toto_titi_CT- | otot_itit
- I want to have only ( colones $7,$13 and $15) with code 4003 and 4002. for colone $13 I want to have the whole name untill _CT- or _GC-
1- I used the command egrep with awk
#egrep -i... (2 Replies)
Discussion started by: georg2014
2 Replies
LEARN ABOUT DEBIAN
graphics::primitive::insets
Graphics::Primitive::Insets(3pm) User Contributed Perl Documentation Graphics::Primitive::Insets(3pm)NAME
Graphics::Primitive::Insets - Space between things
DESCRIPTION
Graphics::Primitive::Insets represents the amount of space that surrounds something. This object can be used to represent either padding
or margins (in the CSS sense, one being inside the bounding box, the other being outside)
SYNOPSIS
use Graphics::Primitive::Insets;
my $insets = Graphics::Primitive::Insets->new({
top => 5,
bottom => 5,
left => 5,
right => 5
});
METHODS
Constructor
new Creates a new Graphics::Primitive::Insets.
Instance Methods
as_array
Return these insets as an array in the form of top, right, bottom and left.
bottom
Set/Get the inset from the bottom.
equal_to
Determine if these Insets are equal to another.
left
Set/Get the inset from the left.
right
Set/Get the inset from the right.
top Set/Get the inset from the top.
zero
Sets all the insets (top, left, bottom, right) to 0.
AUTHOR
Cory Watson, "<gphat@cpan.org>"
SEE ALSO perl(1)COPYRIGHT & LICENSE
Copyright 2008-2010 by Cory G Watson.
This program is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
perl v5.12.3 2010-08-21 Graphics::Primitive::Insets(3pm)