1. Not sure what your original code was before you edited it as your updated code is identical.
2. There is a space in the first position of each line on your input file so the condition ^> will not find any lines.
3. What is the requirement as to why you need to use substr as your solution appears to work with a slight modification?
4. Based on your input and output files, length>=7 should be length>7 in your solution after removing the spaces in first position of each line.
What is the more efficient way to do this (awk only and default FS) ?
$ echo "jefe@alm"|awk '{pos = index($0, "@");printf ("USER: %s\n",substr ($0,1,pos-1))}'
USER: jefe
Thx in advance (2 Replies)
Hi,
My input file is
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
41;2;xxxx;yyyyy....
..
..
I need to change the second field value from 2 to 1. i.e.,
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
41;1;xxxx;yyyyy....
..
..
Thanks in advance. (9 Replies)
Hi,
I have a long string like,
aabab|bcbcbcbbc|defgh|paswd123 dedededede|efef|ghijklmn|paswd234 ghghghghgh|ijijii|klllkkk|paswd345 lmlmlmmm|nononononn|opopopopp|paswd456
This string is devided into one space between substrings. This substrings are,
aabab|bcbcbcbbc|defgh|paswd123... (6 Replies)
Hi I am trying to run this command in ksh ...its not working
$line="123356572867116w1671716"
actual_length = 16
cut_line=`awk 'BEGIN{print substr(ARGV,1,actual_length)}' "$line"`
the substr is not giving me an output
how can i make it done
can anyone hwlp me on this
cut_line=`awk... (2 Replies)
Hi, i'm a newbie and i don't know unix...
I'm a dba oracle.
I need to cat the content of a file like this:
> ps -eaf|grep pmon
oracle 221422 1 0 Sep 17 - 7:20 ora_pmon_ORCL
oracle 405626 1 0 Sep 17 - 8:39 ora_pmon_ORCL1
oracle 491534 1 0 ... (3 Replies)
Hello life savers!!
Is there any way to use substr in awk command for returning one part of a string from declared start and stop point?
I mean I know we have this:
substr(string, start, length)
Do we have anything like possible to use in awk ? :
substr(string, start, stop)
... (9 Replies)
I have a command like this:
listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES" else if (substr ($0,37,1)==0 && NR == 3) print "NO"}'
This syntax doesn't work. But I was able to get this to work:
listdb ID923 -l |gawk '{if (substr($0,37,1)==1 && NR == 3)print "YES"}'
... (4 Replies)
Hi,
- In a file test.wmi
Col1 | firstName | lastName
4003 | toto_titi_CT- | otot_itit
- I want to have only ( colones $7,$13 and $15) with code 4003 and 4002. for colone $13 I want to have the whole name untill _CT- or _GC-
1- I used the command egrep with awk
#egrep -i... (2 Replies)
Discussion started by: georg2014
2 Replies
LEARN ABOUT FREEBSD
fmt
FMT(1) BSD General Commands Manual FMT(1)NAME
fmt -- simple text formatter
SYNOPSIS
fmt [-cmnps] [-d chars] [-l num] [-t num] [goal [maximum] | -width | -w width] [file ...]
DESCRIPTION
The fmt utility is a simple text formatter which reads the concatenation of input files (or standard input if none are given) and produces on
standard output a version of its input with lines as close to the goal length as possible without exceeding the maximum. The goal length
defaults to 65 and the maximum to 10 more than the goal length. Alternatively, a single width parameter can be specified either by prepend-
ing a hyphen to it or by using -w. For example, ``fmt -w 72'', ``fmt -72'', and ``fmt 72 72'' all produce identical output. The spacing at
the beginning of the input lines is preserved in the output, as are blank lines and interword spacing. Lines are joined or split only at
white space; that is, words are never joined or hyphenated.
The options are as follows:
-c Center the text, line by line. In this case, most of the other options are ignored; no splitting or joining of lines is done.
-m Try to format mail header lines contained in the input sensibly.
-n Format lines beginning with a '.' (dot) character. Normally, fmt does not fill these lines, for compatibility with nroff(1).
-p Allow indented paragraphs. Without the -p flag, any change in the amount of whitespace at the start of a line results in a new para-
graph being begun.
-s Collapse whitespace inside lines, so that multiple whitespace characters are turned into a single space. (Or, at the end of a sen-
tence, a double space.)
-d chars
Treat the chars (and no others) as sentence-ending characters. By default the sentence-ending characters are full stop ('.'), ques-
tion mark ('?') and exclamation mark ('!'). Remember that some characters may need to be escaped to protect them from your shell.
-l number
Replace multiple spaces with tabs at the start of each output line, if possible. Each number spaces will be replaced with one tab.
The default is 8. If number is 0, spaces are preserved.
-t number
Assume that the input files' tabs assume number spaces per tab stop. The default is 8.
The fmt utility is meant to format mail messages prior to sending, but may also be useful for other simple tasks. For instance, within vis-
ual mode of the ex(1) editor (e.g., vi(1)) the command
!}fmt
will reformat a paragraph, evening the lines.
ENVIRONMENT
The LANG, LC_ALL and LC_CTYPE environment variables affect the execution of fmt as described in environ(7).
SEE ALSO fold(1), mail(1), nroff(1)HISTORY
The fmt command appeared in 3BSD.
The version described herein is a complete rewrite and appeared in FreeBSD 4.4.
AUTHORS
Kurt Shoens
Liz Allen (added goal length concept)
Gareth McCaughan
BUGS
The program was designed to be simple and fast - for more complex operations, the standard text processors are likely to be more appropriate.
When the first line of an indented paragraph is very long (more than about twice the goal length), the indentation in the output can be
wrong.
The fmt utility is not infallible in guessing what lines are mail headers and what lines are not.
BSD August 2, 2004 BSD