I wrote myself a small little shell script to clean up a file I have issues with. In particular, I am stripping down a fully qualified host/domain name to just the hostname itself. The script works, but from a performance standpoint, it's not very fast and I will be working with large data sets.
Here is a sample dataset:
My code is below:
As you can see, not an elegant solution, but it creates the wanted output (strip FQDN from field 2). My awk is a bit rusty and my perl is basic. If someone has a faster, cleaner way of doing this, i'm all ears.
I've got a diff command running in a shell script that writes the ouput to a new file. In the new file there is a ">" at the beginning of each line. The output file is going to be used by another program and that character makes the file useless.
What I'm getting in the new file:
> 2007-09-27... (5 Replies)
Hi there, if i have some strings ie
test_324423
test_242332
test_767667
but I only want the number part (the bolded bit) how do I strip the leftmost 5 characters from the output so that i will have just
324423
242332
767667
any help would be greatly appreciated
Gary (5 Replies)
I am trying to strip out certain characters from a string on both (left & right) sides. For example, line=see@hear|touch, i only want to echo the "hear" part. Well i have tried this approach:
line=see@hear|touch
templine=${line#*@} #removed "see@"
echo ${templine%%\|*} #removed... (4 Replies)
Hi everyone,
My problem is strange, I cannot think of why this is happening.
I have a set of data that looks like this:
Although it does not look it, the fields are tab delimited. I have made sure of this, and awk does recognize them as such. However, it divides what I would expect... (2 Replies)
I want to create a temp file which is named based on a search string. The search string may contain spaces or characters that aren't supposed to be used in filenames so I want to strip those out.
My thought was to use 'tr' with but the result is the opposite of what I want:
$ echo "test... (5 Replies)
i have a file like this
1111_2222#$#$dudgfdk
11111111_343434#$#$334
1111_22222#43445667
i want to remove all those charachetrs from #
how can i do this
Thank in advance
Saravanan (4 Replies)
I'm using a shell script to get user input with this command:
read UserInput
I would then like to take the "UserInput" variable and strip out all of the following characters, regardless of where they appear in the variable or how many occurrences there are:
\/":|<>+=;,?*@
I'm not sure... (5 Replies)
Hi. I need to trace on Unix level number of connections to an Oracle database. The listener runs on port 1521.
The following is run:
oracle@server03 >lsof -Pni |grep ".1521" |grep IPv4 | awk {'print $5'}|cut -d: -f 1|sort|uniq -c|sort -nk 1
87 IPv4
oracle@server03 >
I need to append... (2 Replies)
Dear experts,
my problem is pretty tricky.
I want to change a file (see attached input.txt), according to another file (help.txt). The output that is desired is in output.txt. The example is attached.
Note that
-dashes should not be treated specially, they are considered normal characters,... (2 Replies)
so i have strings such as this:
'postfix/local#2,5#|CRON.*12062.*root.*CMD#2,5#|roice.*NQN1#1,2#|toysprc#1,4#'
i need to get rid of the "#" and the numbers between them for each of the strings above. so the desired output should be:
... (1 Reply)
Discussion started by: SkySmart
1 Replies
LEARN ABOUT PHP
geoip_country_code_by_name
GEOIP_COUNTRY_CODE_BY_NAME(3) 1 GEOIP_COUNTRY_CODE_BY_NAME(3)geoip_country_code_by_name - Get the two letter country codeSYNOPSIS
string geoip_country_code_by_name (string $hostname)
DESCRIPTION
The geoip_country_code_by_name(3) function will return the two letter country code corresponding to a hostname or an IP address.
PARAMETERS
o $hostname
- The hostname or IP address whose location is to be looked-up.
RETURN VALUES
Returns the two letter ISO country code on success, or FALSE if the address cannot be found in the database.
EXAMPLES
Example #1
A geoip_country_code_by_name(3) example
This will print where the host example.com is located.
<?php
$country = geoip_country_code_by_name('www.example.com');
if ($country) {
echo 'This host is located in: ' . $country;
}
?>
The above example will output:
This host is located in: US
NOTES
Caution
Please see http://www.maxmind.com/en/iso3166 for a complete list of possible return values, including special codes.
SEE ALSO geoip_country_code3_by_name(3), geoip_country_name_by_name(3).
PHP Documentation Group GEOIP_COUNTRY_CODE_BY_NAME(3)