Hi,
I am trying to do achieving of files by months.
find /test -name \*.* -mtime +30
will give me the result of all modified files after 30 days.
But lets say i want to list all files that is modified in last months... what is the command to do it?
Thanks! (13 Replies)
Help please! I need to read the calendar and put the date of the third Friday of each month into a variable for comparison in an "if" statement. How would I do this?
Thnx,
leslie02 (10 Replies)
I know I can't schedule this in cron and would have to write a wrapper around my script and schedule it in cron ....but not sure how do to this?
How do I exclude Monday if the 2nd day of the month falls on a Monday?
Thanks.
I tried this:
0 0 2 * 0,2-6 command
And I know this doesnt... (2 Replies)
Hi All
Any one please suggest me...
I have one directory every monday one file will be created in that directory. so if the file is created on monday or not i need check first.
How can write a script??? if the file is not created i want to quit from script.
Thanks
K.Srinivas (5 Replies)
Hi All,
I need to find last two files for the month.
lets say there are following files in directory
-rwxr-xr-x 1 user userg 1596 Mar 19 15:43 c.txt
-rwxr-xr-x 1 user userg 1596 Mar 21 15:43 d.txt
-rwxr-xr-x 1 user userg 1596 Mar 22 15:43 f.txt
-rwxr-xr-x 1... (14 Replies)
Hi,
I want two dates one will be the current date and the other one will be just one month before. Say if current month is 11/4/2014 then the other date should be 11/3/2014.
#!/bin/ksh
currentDtae=`date`
oneMonthBefore= ?
I dont know how to do it. Went through some of the related threads... (15 Replies)
Discussion started by: Sharma331
15 Replies
LEARN ABOUT PHP
datetime.sub
DATETIME.SUB(3) 1 DATETIME.SUB(3)DateTime::sub - Subtracts an amount of days, months, years, hours, minutes and seconds from a DateTime object
Object oriented style
SYNOPSIS
public DateTime DateTime::sub (DateInterval $interval)
DESCRIPTION
Procedural style
DateTime date_sub (DateTime $object, DateInterval $interval)
Subtracts the specified DateInterval object from the specified DateTime object.
PARAMETERS
o $object
-Procedural style only: A DateTime object returned by date_create(3). The function modifies this object.
o $interval
- A DateInterval object
RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure.
EXAMPLES
Example #1
DateTime.sub(3) example
Object oriented style
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P10D'));
echo $date->format('Y-m-d') . "
";
?>
Procedural style
<?php
$date = date_create('2000-01-20');
date_sub($date, date_interval_create_from_date_string('10 days'));
echo date_format($date, 'Y-m-d');
?>
The above examples will output:
2000-01-10
Example #2
Further DateTime.sub(3) examples
<?php
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('PT10H30S'));
echo $date->format('Y-m-d H:i:s') . "
";
$date = new DateTime('2000-01-20');
$date->sub(new DateInterval('P7Y5M4DT4H3M2S'));
echo $date->format('Y-m-d H:i:s') . "
";
?>
The above example will output:
2000-01-19 13:59:30
1992-08-15 19:56:58
Example #3
Beware when subtracting months
<?php
$date = new DateTime('2001-04-30');
$interval = new DateInterval('P1M');
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
$date->sub($interval);
echo $date->format('Y-m-d') . "
";
?>
The above example will output:
2001-03-30
2001-03-02
NOTES DateTime.modify(3) is an alternative when using PHP 5.2.
SEE ALSO DateTime.add(3), DateTime.diff(3), DateTime.modify(3).
PHP Documentation Group DATETIME.SUB(3)