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Full Discussion: Transpose a file
Top Forums UNIX for Dummies Questions & Answers Transpose a file Post 302948379 by RudiC on Monday 29th of June 2015 10:53:33 AM
Old 06-29-2015
Try
Code:
awk     'NR>1   {LN[$4]; HD[$5]; MX[$4,$5]=$2}
         END    {               printf "%10s", ""; for (i in HD) printf "%10s", i; print "";
                 for (j in LN) {printf "%10s",j;   for (i in HD) printf "%10s", MX[j,i]; print ""}
                }
        ' file
                            10       7.1       7.2      11.1         1         2         3         4         5         6         8         9
       C01                             T                                       T         T         T         T         T                    
       D02                                                 T                                                                     C         C
        11        xx                                                                                                                        
       A01                                                           T         T         T                                                  
       A02                                                                                         T         T         T                    
       B01                   T                  NA                                                                               T         T
       B10                                                           T

The line with "11" is there as your input file has a missing entry for it.
This User Gave Thanks to RudiC For This Post:
 

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DB2_FETCH_ASSOC(3)							 1							DB2_FETCH_ASSOC(3)

db2_fetch_assoc - Returns an array, indexed by column name, representing a row in a result set

SYNOPSIS
array db2_fetch_assoc (resource $stmt, [int $row_number = -1]) DESCRIPTION
Returns an array, indexed by column name, representing a row in a result set. PARAMETERS
o $stmt - A valid stmt resource containing a result set. o $row_number - Requests a specific 1-indexed row from the result set. Passing this parameter results in a PHP warning if the result set uses a forward-only cursor. RETURN VALUES
Returns an associative array with column values indexed by the column name representing the next or requested row in the result set. Returns FALSE if there are no rows left in the result set, or if the row requested by $row_number does not exist in the result set. EXAMPLES
Example #1 Iterating through a forward-only cursor If you call db2_fetch_assoc(3) without a specific row number, it automatically retrieves the next row in the result set. <?php $sql = "SELECT id, name, breed, weight FROM animals ORDER BY breed"; $stmt = db2_prepare($conn, $sql); $result = db2_execute($stmt); while ($row = db2_fetch_assoc($stmt)) { printf ("%-5d %-16s %-32s %10s ", $row['ID'], $row['NAME'], $row['BREED'], $row['WEIGHT']); } ?> The above example will output: 0 Pook cat 3.20 5 Rickety Ride goat 9.70 2 Smarty horse 350.00 Example #2 Retrieving specific rows with db2_fetch_assoc(3) from a scrollable cursor If your result set uses a scrollable cursor, you can call db2_fetch_assoc(3) with a specific row number. The following example retrieves every other row in the result set, starting with the second row. <?php $sql = "SELECT id, name, breed, weight FROM animals ORDER BY breed"; $result = db2_exec($stmt, $sql, array('cursor' => DB2_SCROLLABLE)); $i=2; while ($row = db2_fetch_assoc($result, $i)) { printf ("%-5d %-16s %-32s %10s ", $row['ID'], $row['NAME'], $row['BREED'], $row['WEIGHT']); $i = $i + 2; } ?> The above example will output: 0 Pook cat 3.20 5 Rickety Ride goat 9.70 2 Smarty horse 350.00 SEE ALSO
db2_fetch_array(3), db2_fetch_both(3), db2_fetch_object(3), db2_fetch_row(3), db2_result(3). PHP Documentation Group DB2_FETCH_ASSOC(3)
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