Pattern match a path anywhere in the line and replace it with new path
I want to pattern match only path part from below and replace them with new path string.
paths(ex:/fldrA/fldrBaf/fldrCaa) from above will be dynamic. How do I do that?
I need to replace the line containing "STAGE_DB" with the line
"STAGE_DB $DB # database that contains the table being loaded ($workingDB)"
Here $DB is passed during the runtime.
How can I do this?
Thanks,
Kousikan (2 Replies)
Hi,
I am looking for any script which can do the following.
have to read a pattern from fileA and copy it to fileB.
fileA:
...
...
Header
...
...
..p1
...
...
fileB:
....
....
Header (3 Replies)
I have a pattern
username:x:32005:32006::/usr/local/user:/bin/bash
I need to match the line containing username and replace /bin/bash with /usr/local/my/bin/noshell
So it becomes
username:x:32005:32006::/usr/local/user:/usr/local/my/bin/noshell (7 Replies)
Hi How Are you?
I am doing fine!
I need to go now?
I will see you tomorrow!
Basically I need to replace the entire line containing "doing" with a blank line:
I need to the following output:
Hi How Are you?
I need to go now?
I will see you tomorrow!
Thanks in advance.... (1 Reply)
Im using the command below , but thats not the output that i want. it only prints the odd and even numbers.
awk '{if(NR%2){print $0 > "1"}else{print $0 > "2"}}'
Im hoping for something like this
file1:
Text hi this is just a test
text1 text2 text3 text4 text5 text6
Text hi... (2 Replies)
Hi All,
Can you please provide some pointers to move files from Base path to multiple paths in efficient way.Folder Structure is already created.
/Path/AdminUser/User1/1111/Reports/aaa.txt to /Path/User1/1111/Reports/aaa.txt
/Path/AdminUser/User1/2222/Reports/bbb.txt to... (6 Replies)
Currently I am using this laborious command
lvdisplay | awk '/LV Path/ {p=$3} /LV Name/ {n=$3} /VG Name/ {v=$3} /Block device/ {d=$3; sub(".*:", "/dev/dm-", d); printf "%s\t%s\t%s\n", p, "/dev/mapper/"v"-"n, d}'
Would like to know if there is any shorter method to get this mapping of... (2 Replies)
Hi,
I need to do find and replace, but the pattern is not full known.
for example,
my file has /proj/app-d1/sun or /data/site-d1/conf
here app-d1 and site-d1 is not constant. It may be different in different files. common part is /proj/xx/sun and /data/xxx/conf
i want to find where ever... (6 Replies)
Discussion started by: rbalaj16
6 Replies
LEARN ABOUT HPUX
getbuildlog
GETBUILDLOG(1) General Commands Manual GETBUILDLOG(1)NAME
getbuildlog - download build logs from Debian auto-builders
SYNOPSIS
getbuildlog package [version-pattern] [architecture-pattern]
DESCRIPTION
getbuildlog downloads build logs of package from Debian auto-builders. It downloads build logs of all versions and for all architectures if
version-pattern and architecture-pattern are not specified or empty, otherwise only build logs whose versions match version-pattern and
build logs whose architectures match architecture-pattern will be downloaded. The version and architecture patterns are interpreted as
extended regular expressions as described in grep(1).
If version-pattern is "last" then only the logs for the most recent version of package found on buildd.debian.org will be downloaded.
If version-pattern is "last-all" then the logs for the most recent version found on each build log index will be downloaded.
OPTIONS -h, --help
Show usage information and examples.
-V, --version
Show version and copyright information.
EXAMPLES
getbuildlog hello 2.2-1 amd64
Download amd64 build log for hello version 2.2-1.
getbuildlog glibc "" mips.*
Download mips(el) build logs of all glibc versions.
getbuildlog wesnoth .*bpo.*
Download all build logs of backported wesnoth versions.
AUTHOR
Written by Frank S. Thomas <fst@debian.org>.
DEBIAN Debian Utilities GETBUILDLOG(1)