[...]
print -n {$second#?} gives me the 1043 but I have been unsuccessful assigning this result to a variable - I tried company = {$second#?} but company has no value.
I'm new to this, so any help would be appreciated.
Code:
printf -v number "%s" ${second#\#}
Now, what you want lives in a variable named `number'
Hi,
I'm quite new to scripting and I want to modify following line of an existing script:
MYVAR=`subst |grep 'L:\\\:' | sed -e 's/.*\\\//'`;
What I have to do is to use the content of a variable instead of the constant expression 'L:\\\:' as the grep string to be matched.
Assuming I already... (5 Replies)
How...
can I read input by a user character by cahracter. And assign each character from the string to a variable?
Any help would be greatly appreciated!
Thank you! (1 Reply)
Hi Friends...
Please assist me to assign the result of a SQL query that results two column, to two variables.
Pls find the below code that I write for assigning one column to one variable. and please correct if anything wrong..
#! /bin/sh
no='
sqlplus -s uname/password@DBname... (4 Replies)
Hi friends,
firstly, i can run following expression and i took 100 value.
sqlplus -s username/password@TTTEST @umt.sql
umt.sql exists "select t.deger from parametre t where t.id=30".
result of this query =100
i need to assign this value(100) to variable(for example x... (2 Replies)
Hi
im trying to assign the result of the db2 command to a variable inside a shell script...
: tab_cnt=`db2 "select count(*) from syscat.tables where tabname = 'ABC' and tabschema = 'MATT01'" |head -4|tail +4|cut -c 11`
: echo $tab_cnt
when i echo im getting a blank value.. im expecting... (1 Reply)
I see a millioin ways to do this with echo, but what I wan to do is assign a variable the "nth" character of an incoming parameter to a ksh script.
$1 will be "pia"
I need to assign the first character to stmttype. (10 Replies)
Hi,
I have the following command that lists all the .o files from all the directories except of vwin (which I don't want it)
for i in `ls -d */*.o|awk '$0 !~ "vwin"'`; do echo $i; done
The result is something like that
dir1/file1.o
dir1/file2.o
dir2/file3.o
etc.
So, I want to create a... (9 Replies)
Hello,
I have searched but failed to find what exactly im looking for,
I need to eliminate first "." in a output so i can use something like the following
echo "./abc/20141127" | nawk '{gsub("^.","");print}'
what i want is to use gsub result later on, how could i achieve it?
Let say... (4 Replies)
Hi
How to pass echo output to a variable ?
Does below awk command will get the last character of hostname and assign to a variable - "svr" ?
svr=$( echo `hostname` | awk '{print substr($0,length,1)}' )
Thanks.
Please use CODE tags when dsplaying code segments, sample input, and sample... (7 Replies)
Discussion started by: Lim
7 Replies
LEARN ABOUT DEBIAN
shell-quote
SHELL-QUOTE(1p) User Contributed Perl Documentation SHELL-QUOTE(1p)NAME
shell-quote - quote arguments for safe use, unmodified in a shell command
SYNOPSIS
shell-quote [switch]... arg...
DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands
or files with embedded white space or shell globbing characters safely. Here are a few examples.
EXAMPLES
ssh preserving args
When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and
passes them to "$SHELL -c". This doesn't work as intended:
ssh host touch 'hi there' # fails
It creates 2 files, hi and there. Instead, do this:
cmd=`shell-quote touch 'hi there'`
ssh host "$cmd"
This gives you just 1 file, hi there.
process find output
It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to
split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote:
eval set -- `find -type f -print0 | xargs -0 shell-quote --`
debug shell scripts
shell-quote is better than echo for debugging shell scripts.
debug() {
[ -z "$debug" ] || shell-quote "debug:" "$@"
}
With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can.
save a command for later
shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command
you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are
things the user can't pass through), you can do something like this:
user_switches=
while [ $# != 0 ]
do
case x$1 in
x--pass-through)
[ $# -gt 1 ] || die "need an argument for $1"
user_switches="$user_switches "`shell-quote -- "$2"`
shift;;
# process other switches
esac
shift
done
# later
eval "shell-quote some-command $user_switches my args"
OPTIONS --debug
Turn debugging on.
--help
Show the usage message and die.
--version
Show the version number and exit.
AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions.
AUTHOR
Roderick Schertler <roderick@argon.org>
perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)