cat .servers | while read LINE; do
ssh jason@$LINE $1
done
exit 1
./command.ksh "ls -l ~jason"
Why does this ONLY iterate on the first server in the list? It's not doing the command on all the servers in the list, what am I missing?
Thanks!
JP (2 Replies)
Howdie everyone...
I have a shell script RemoveFiles.sh
Inside this file, it only has two commands as below:
rm -f ../../reportToday/temp/*
rm -f ../../report/*
My problem is that when i execute this script, nothing happened. Files remained unremoved. I don't see any error message as it... (2 Replies)
Hello, the ls -d command to only list directories in a directory doesn't seem to work on Solaris and the man command says to use that combination: ls -d
Anyone have the same problem and find a resolve?
Thanks
BobK (9 Replies)
Hi. I've been playing around a bit. This isn't for any practical purpose-- it's really just a theoretical exercise. I wrote this little thing:
foreach num ( 6 5 4 )
awk -v "number=$num" 'BEGIN{for(x=0;x<$number;x++) printf "-"; printf "\n"}'
end
I would expect the following output:
... (3 Replies)
Hi
I have put alias ll='ls -la' in .profile file but it doesn't work.
On hand it works it looks like the .profile file is not beeing read.
How to check whitch file is loaded? ,profile? .bash_profile?
My system: SunOS mion 5.10 Generic
Shell: /bin/pfksh
Thanks (2 Replies)
i want to get the value for column 4rth when i =4. please guide what i am doing wrong. thanks
var=`cat file.csv`
for i in $var; do {
if ; then
var4=$var4+$i
fi
echo $i
}
done
I am geting this error message "0403-009 The specified number is not valid for this command." (8 Replies)
I edited sudoers like this:vi /etc/sudoers
subex ALL =(root) NOPASSWD: /usr/ccs/bin/pstack
But the respective user still is prompted for password, and even when the right password is used, the command is still not launched.$sudo usr/ccs/bin/pstack 26557
We trust you have received the usual... (5 Replies)
Discussion started by: black_fender
5 Replies
LEARN ABOUT MOJAVE
escape
escape(1) Mail Avenger 0.8.3 escape(1)NAME
escape - escape shell special characters in a string
SYNOPSIS
escape string
DESCRIPTION
escape prepends a "" character to all shell special characters in string, making it safe to compose a shell command with the result.
EXAMPLES
The following is a contrived example showing how one can unintentionally end up executing the contents of a string:
$ var='; echo gotcha!'
$ eval echo hi $var
hi
gotcha!
$
Using escape, one can avoid executing the contents of $var:
$ eval echo hi `escape "$var"`
hi ; echo gotcha!
$
A less contrived example is passing arguments to Mail Avenger bodytest commands containing possibly unsafe environment variables. For
example, you might write a hypothetical reject_bcc script to reject mail not explicitly addressed to the recipient:
#!/bin/sh
formail -x to -x cc -x resent-to -x resent-cc
| fgrep "$1" > /dev/null
&& exit 0
echo "<$1>.. address does not accept blind carbon copies"
exit 100
To invoke this script, passing it the recipient address as an argument, you would need to put the following in your Mail Avenger rcpt
script:
bodytest reject_bcc `escape "$RECIPIENT"`
SEE ALSO avenger(1),
The Mail Avenger home page: <http://www.mailavenger.org/>.
BUGS
escape is designed for the Bourne shell, which is what Mail Avenger scripts use. escape might or might not work with other shells.
AUTHOR
David Mazieres
Mail Avenger 0.8.3 2012-04-05 escape(1)