To the above script, I passed 2 parameters and the program control doesn't enter inside "until" loop. If I change it to until [[ $# -le 0 ]] then it does work.
Why numeric comparison is not working with -ne and works with -le?
thank you
Last edited by Scrutinizer; 06-04-2015 at 01:42 PM..
Reason: code tags
cat .servers | while read LINE; do
ssh jason@$LINE $1
done
exit 1
./command.ksh "ls -l ~jason"
Why does this ONLY iterate on the first server in the list? It's not doing the command on all the servers in the list, what am I missing?
Thanks!
JP (2 Replies)
Howdie everyone...
I have a shell script RemoveFiles.sh
Inside this file, it only has two commands as below:
rm -f ../../reportToday/temp/*
rm -f ../../report/*
My problem is that when i execute this script, nothing happened. Files remained unremoved. I don't see any error message as it... (2 Replies)
Hello, the ls -d command to only list directories in a directory doesn't seem to work on Solaris and the man command says to use that combination: ls -d
Anyone have the same problem and find a resolve?
Thanks
BobK (9 Replies)
Hi. I've been playing around a bit. This isn't for any practical purpose-- it's really just a theoretical exercise. I wrote this little thing:
foreach num ( 6 5 4 )
awk -v "number=$num" 'BEGIN{for(x=0;x<$number;x++) printf "-"; printf "\n"}'
end
I would expect the following output:
... (3 Replies)
Hi
I have put alias ll='ls -la' in .profile file but it doesn't work.
On hand it works it looks like the .profile file is not beeing read.
How to check whitch file is loaded? ,profile? .bash_profile?
My system: SunOS mion 5.10 Generic
Shell: /bin/pfksh
Thanks (2 Replies)
i want to get the value for column 4rth when i =4. please guide what i am doing wrong. thanks
var=`cat file.csv`
for i in $var; do {
if ; then
var4=$var4+$i
fi
echo $i
}
done
I am geting this error message "0403-009 The specified number is not valid for this command." (8 Replies)
I edited sudoers like this:vi /etc/sudoers
subex ALL =(root) NOPASSWD: /usr/ccs/bin/pstack
But the respective user still is prompted for password, and even when the right password is used, the command is still not launched.$sudo usr/ccs/bin/pstack 26557
We trust you have received the usual... (5 Replies)
Discussion started by: black_fender
5 Replies
LEARN ABOUT DEBIAN
io::async::pid
IO::Async::PID(3pm) User Contributed Perl Documentation IO::Async::PID(3pm)NAME
"IO::Async::PID" - event callback on exit of a child process
SYNOPSIS
use IO::Async::PID;
use POSIX qw( WEXITSTATUS );
use IO::Async::Loop;
my $loop = IO::Async::Loop->new;
my $kid = $loop->fork(
code => sub {
print "Child sleeping..
";
sleep 10;
print "Child exiting
";
return 20;
},
);
print "Child process $kid started
";
my $pid = IO::Async::PID->new(
pid => $kid,
on_exit => sub {
my ( $self, $exitcode ) = @_;
printf "Child process %d exited with status %d
",
$self->pid, WEXITSTATUS($exitcode);
},
);
$loop->add( $pid );
$loop->run;
DESCRIPTION
This subclass of IO::Async::Notifier invokes its callback when a process exits.
For most use cases, a IO::Async::Process object provides more control of setting up the process, connecting filehandles to it, sending data
to and receiving data from it.
EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters:
on_exit $exitcode
Invoked when the watched process exits.
PARAMETERS
The following named parameters may be passed to "new" or "configure":
pid => INT
The process ID to watch. Must be given before the object has been added to the containing "IO::Async::Loop" object.
on_exit => CODE
CODE reference for the "on_exit" event.
Once the "on_exit" continuation has been invoked, the "IO::Async::PID" object is removed from the containing "IO::Async::Loop" object.
METHODS
$process_id = $pid->pid
Returns the underlying process ID
$pid->kill( $signal )
Sends a signal to the process
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2012-10-24 IO::Async::PID(3pm)