|
|
Sponsored Content
Top Forums
Shell Programming and Scripting
Code to compare date
Post 302945316 by RudiC on Thursday 28th of May 2015 09:05:16 AM
05-28-2015
|
|
10 More Discussions You Might Find Interesting
1. Shell Programming and Scripting
I am currently running the following Korn shell script which works fine:
#!/usr/bin/ksh
count=`db2 -x "select count(*) from schema.tablename"`
echo "count"
I would like to add a "where" clause to the 2nd line that would allow me to get a record count of all the records from schema.tablename... (9 Replies)
Discussion started by: sasaliasim
9 Replies
2. Shell Programming and Scripting
Hi All,
I have problem in my file. It has two date variable.
There are 2 variables which has the values as below
1. START_MONTH = “Date(YYYYMM) format” Ex: 201008
2. END_MONTH = “Date(YYYYMM) format” Ex: 201105
The end date should be greater than start date.
Now we... (3 Replies)
Discussion started by: suresh01_apk
3 Replies
3. Shell Programming and Scripting
In KSH, I am pasting 2 almost identical files together and each one has a date and time on each line. I need to determine if the first instance of the date/time is greater than the 2nd instance of the date/time. If the first instance is greater, I just need to echo that line.
I thought I would... (4 Replies)
Discussion started by: right_coaster
4 Replies
4. Shell Programming and Scripting
Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if ; then
...proceed commands
... (1 Reply)
Discussion started by: kokoro
1 Replies
5. Shell Programming and Scripting
Hi,
I am new to this forum, searched, but for some reason did not find much help, so a new thread.
I am trying to compare date with a string which is in date format , but for some reason, system does not give me the right result.
Date is coming in a file and i am comparing the same with... (2 Replies)
Discussion started by: mkstool
2 Replies
6. Shell Programming and Scripting
hi all,
How to compare two files whether they are same are not...? like i had my input files as 20141201_file.txt and 20141130_file2.txt
how to compare the above files based on date .. like todays file and yesterdays file...? (4 Replies)
Discussion started by: hemanthsaikumar
4 Replies
7. Shell Programming and Scripting
I get the date that's inside a text file and assigned it to a variable. When I grep the date from the file, I get this,
Not After : Jul 28 14:09:57 2017 GMT
So I only crop out the date, with this command
echo $dateFile | cut -d ':' -f 2,4The result would be
Jul 28 14:57 2017 GMT
How do I... (3 Replies)
Discussion started by: Loc
3 Replies
8. UNIX for Beginners Questions & Answers
Can someone help me with the code wherein there is a file f1.txt with different column and 34 column have expiry date and I need to get that and compare with system date and if expiry date is <system date remove those rows and other rows should be moved to new file f2.txt .
I don't want to delete... (2 Replies)
Discussion started by: Stuti
2 Replies
9. Answers to Frequently Asked Questions
I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
Discussion started by: Stuti
1 Replies
10. UNIX for Beginners Questions & Answers
Hi Community!
Following on from this code in another thread:
#!/bin/bash
file_string=`/bin/cat date.txt | /usr/bin/awk '{print $5,$4,$7,$6,$8}'`
file_date=`/bin/date -d "$file_string"`
file_epoch=`/bin/date -d "$file_string" +%s`
now_epoch=`/bin/date +%s`
if
then
#let... (2 Replies)
Discussion started by: Greenage
2 Replies
LEARN ABOUT DEBIAN
linux-version
LINUX-VERSION(1) General Commands Manual LINUX-VERSION(1) NAME
linux-version - operate on Linux kernel version strings SYNOPSIS
linux-version compare VERSION1 OP VERSION2 linux-version sort [--reverse] [VERSION1 VERSION2 ...] linux-version list [--paths] DESCRIPTION
linux-version operates on Linux kernel version strings as reported by uname -r and used in file and directory names. These version strings do not follow the same rules as Debian package version strings and should not be compared as such or as arbitrary strings. compare VERSION1 OP VERSION2 Compare version strings, where OP is a binary operator. linux-version returns success (zero result) if the specified condition is satisfied, and failure (nonzero result) otherwise. The valid operators are: lt le eq ne ge gt sort [--reverse] [VERSION1 VERSION2 ...] Sort the given version strings and print them in order from lowest to highest. If the --reverse option is used, print them in order from highest to lowest. If no version strings are given as arguments, the version strings will instead be read from standard input, one per line. They may be suffixed by arbitrary text after a space, which will be included in the output. This means that, for example: linux-version list --paths | linux-version sort --reverse will list the installed versions and corresponding paths in order from highest to lowest version. list [--paths] List kernel versions installed in the customary location. If the --paths option, show the corresponding path for each version. AUTHOR
linux-version and this manual page were written by Ben Hutchings as part of the Debian linux-base package. 30 March 2011 LINUX-VERSION(1)