I have a text file (file.txt) which has a date in YYYYMMDD format in the fourth column. I need to compare and check if that date matches the last date of each month in the same format for all the rows.
I have been able to figure out the last date of each month. But now I want to match it with with all the rows of fourth column so that by mistake there is no mismatch in any of the rows. I tried this :
Is there a way using a single awk command to get what I need or a loop after this to match the row(s)?
Last edited by rbatte1; 05-28-2015 at 08:57 AM..
Reason: Added ICODE tags and tightened CODE tags
I am currently running the following Korn shell script which works fine:
#!/usr/bin/ksh
count=`db2 -x "select count(*) from schema.tablename"`
echo "count"
I would like to add a "where" clause to the 2nd line that would allow me to get a record count of all the records from schema.tablename... (9 Replies)
Hi All,
I have problem in my file. It has two date variable.
There are 2 variables which has the values as below
1. START_MONTH = “Date(YYYYMM) format” Ex: 201008
2. END_MONTH = “Date(YYYYMM) format” Ex: 201105
The end date should be greater than start date.
Now we... (3 Replies)
In KSH, I am pasting 2 almost identical files together and each one has a date and time on each line. I need to determine if the first instance of the date/time is greater than the 2nd instance of the date/time. If the first instance is greater, I just need to echo that line.
I thought I would... (4 Replies)
Hi! I am trying to read a file and every line has a specific date as one of its fields.
I want to take that date and compare it to the date today plus 6 days.
while read line
do
date=substr($line, $datepos, 8) #date is expected to be YYYYMMDD
if ; then
...proceed commands
... (1 Reply)
Hi,
I am new to this forum, searched, but for some reason did not find much help, so a new thread.
I am trying to compare date with a string which is in date format , but for some reason, system does not give me the right result.
Date is coming in a file and i am comparing the same with... (2 Replies)
hi all,
How to compare two files whether they are same are not...? like i had my input files as 20141201_file.txt and 20141130_file2.txt
how to compare the above files based on date .. like todays file and yesterdays file...? (4 Replies)
I get the date that's inside a text file and assigned it to a variable. When I grep the date from the file, I get this,
Not After : Jul 28 14:09:57 2017 GMT
So I only crop out the date, with this command
echo $dateFile | cut -d ':' -f 2,4The result would be
Jul 28 14:57 2017 GMT
How do I... (3 Replies)
Can someone help me with the code wherein there is a file f1.txt with different column and 34 column have expiry date and I need to get that and compare with system date and if expiry date is <system date remove those rows and other rows should be moved to new file f2.txt .
I don't want to delete... (2 Replies)
I m working on shell scripting and I m stuck where in my .txt file there is column as expiry date and I need to compare that date with system date and need to remove all the rows where expiry date is less than system date and create a new .txt with update. (1 Reply)
Hi Community!
Following on from this code in another thread:
#!/bin/bash
file_string=`/bin/cat date.txt | /usr/bin/awk '{print $5,$4,$7,$6,$8}'`
file_date=`/bin/date -d "$file_string"`
file_epoch=`/bin/date -d "$file_string" +%s`
now_epoch=`/bin/date +%s`
if
then
#let... (2 Replies)
Discussion started by: Greenage
2 Replies
LEARN ABOUT OSX
ncal
CAL(1) BSD General Commands Manual CAL(1)NAME
cal, ncal -- displays a calendar and the date of easter
SYNOPSIS
cal [-jy] [[month] year]
cal [-j] -m month [year]
ncal [-jJpwy] [-s country_code] [[month] year]
ncal [-Jeo] [year]
DESCRIPTION
The cal utility displays a simple calendar in traditional format and ncal offers an alternative layout, more options and the date of easter.
The new format is a little cramped but it makes a year fit on a 25x80 terminal. If arguments are not specified, the current month is dis-
played.
The options are as follows:
-J Display Julian Calendar, if combined with the -e option, display date of easter according to the Julian Calendar.
-e Display date of easter (for western churches).
-j Display Julian days (days one-based, numbered from January 1).
-m month
Display the specified month.
-o Display date of orthodox easter (Greek and Russian Orthodox Churches).
-p Print the country codes and switching days from Julian to Gregorian Calendar as they are assumed by ncal. The country code as deter-
mined from the local environment is marked with an asterisk.
-s country_code
Assume the switch from Julian to Gregorian Calendar at the date associated with the country_code. If not specified, ncal tries to
guess the switch date from the local environment or falls back to September 2, 1752. This was when Great Britain and her colonies
switched to the Gregorian Calendar.
-w Print the number of the week below each week column.
-y Display a calendar for the specified year.
A single parameter specifies the year (1 - 9999) to be displayed; note the year must be fully specified: ``cal 89'' will not display a calen-
dar for 1989. Two parameters denote the month and year; the month is either a number between 1 and 12, or a full or abbreviated name as
specified by the current locale. Month and year default to those of the current system clock and time zone (so ``cal -m 8'' will display a
calendar for the month of August in the current year).
A year starts on Jan 1.
SEE ALSO calendar(3), strftime(3)HISTORY
A cal command appeared in Version 5 AT&T UNIX. The ncal command appeared in FreeBSD 2.2.6.
AUTHORS
The ncal command and manual were written by Wolfgang Helbig <helbig@FreeBSD.org>.
BUGS
The assignment of Julian--Gregorian switching dates to country codes is historically naive for many countries.
BSD November 23, 2004 BSD