Sorry that I made a mistake for the sample output, it is indeed to remove all spaces as follows:
and I want to have the output from awk -F'|' '{print $1","$2","$3","$4","$5","$6","$7","$8","$9","$10}'` becomes:
Sorry for any inconvenience caused
Paul
Last edited by rbatte1; 05-26-2015 at 01:23 PM..
Reason: Added CODE & ICODE tags
Hi All,
file_1.txt contains
aaa bbbb hhhh
vvvvv mmmmm iiiii
What i want is to search for the first coloumn of each line using awk.i.e as below:
awk '/aaa/ {printf(<>)}' file_1.txt
The print part (<>) should contain all the values(or coloumns ) in the particular line(here it... (8 Replies)
I want a user to be able to paste in a string like "01 3F 20 1F" and have the script reformat it to "013F201F" to pass it on to the next step.
I was trying to figure it out with awk but wasnt working well.
Never mind, found answer. did not know about tr :) (7 Replies)
Hello All,
I am trying to remove all tabspaces and all blankspaces from my file using sed & awk, but not getting proper code. Please help me out.
My file is like this (<b> means one blank space, <t> means one tab space)-
$ cat file
NARESH<b><b><b>KUMAR<t><t>PRADHAN... (3 Replies)
Hello all,
I want to list the file contents of the directory and number them. I am using la and awk to do it now,
#ls |awk '{print NR "." $1}'
1. alpha
2. beta
3. gamma
The problem I have is that some files might also have some spaces in the filenames.
#ls
alpha beta gamma ... (7 Replies)
How to print the strings within a line between two spaces .
<ns1:providerErrorCode>141</ns1:providerErrorCode> <ns1:providerErrorText>business_rule_exception-Server.404:Cannot proceed because the subscriber with phone number is either suspended or the account has an unpaid... (8 Replies)
When I use:
find . -ls | awk 'BEGIN { OFS = ";"} {print $1,$2,$11}'I get a nice result, yet the files with spaces in it show only the first word and all other characters after the blank space are not printed.
e.g. 'file with a blank space'
is printed
file
'file_with a blank space'
is... (7 Replies)
I have a one-line command,
lsusb | awk '{ $1=""; $2=""; $3=""; $4=""; $5=""; $6=""; print $0 }'
It works, and gives the results I expect, I was just wondering if I am missing some easier way to nullify the first 6 column variables?
Something like,
lsusb | awk '{ $(1-6)=""; print $0 }'
But... (10 Replies)
Hi,
I'm using awk to print columns from a tab delimited text file:
awk '{print " "$2" "$3" $6"}' file
The problem I have is column 6 contains text with spaces etc which means awk only prints the first word.
How can I tell awk to print the whole column content as column 6?
Thanks, (10 Replies)
Discussion started by: keenboy100
10 Replies
LEARN ABOUT DEBIAN
io::async::timer::absolute
IO::Async::Timer::Absolute(3pm) User Contributed Perl Documentation IO::Async::Timer::Absolute(3pm)NAME
"IO::Async::Timer::Absolute" - event callback at a fixed future time
SYNOPSIS
use IO::Async::Timer::Absolute;
use POSIX qw( mktime );
use IO::Async::Loop;
my $loop = IO::Async::Loop->new;
my @time = gmtime;
my $timer = IO::Async::Timer::Absolute->new(
time => mktime( 0, 0, 0, $time[4]+1, $time[5], $time[6] ),
on_expire => sub {
print "It's midnight
";
$loop->stop;
},
);
$loop->add( $timer );
$loop->run;
DESCRIPTION
This subclass of IO::Async::Timer implements one-shot events at a fixed time in the future. The object waits for a given timestamp, and
invokes its callback at that point in the future.
For a "Timer" object that waits for a delay relative to the time it is started, see instead IO::Async::Timer::Countdown.
EVENTS
The following events are invoked, either using subclass methods or CODE references in parameters:
on_expire
Invoked when the timer expires.
PARAMETERS
The following named parameters may be passed to "new" or "configure":
on_expire => CODE
CODE reference for the "on_expire" event.
time => NUM
The epoch time at which the timer will expire.
Once constructed, the timer object will need to be added to the "Loop" before it will work.
Unlike other timers, it does not make sense to "start" this object, because its expiry time is absolute, and not relative to the time it is
started.
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2012-10-24 IO::Async::Timer::Absolute(3pm)