Sorry that I made a mistake for the sample output, it is indeed to remove all spaces as follows:
and I want to have the output from awk -F'|' '{print $1","$2","$3","$4","$5","$6","$7","$8","$9","$10}'` becomes:
Sorry for any inconvenience caused
Paul
Last edited by rbatte1; 05-26-2015 at 01:23 PM..
Reason: Added CODE & ICODE tags
Hi All,
file_1.txt contains
aaa bbbb hhhh
vvvvv mmmmm iiiii
What i want is to search for the first coloumn of each line using awk.i.e as below:
awk '/aaa/ {printf(<>)}' file_1.txt
The print part (<>) should contain all the values(or coloumns ) in the particular line(here it... (8 Replies)
I want a user to be able to paste in a string like "01 3F 20 1F" and have the script reformat it to "013F201F" to pass it on to the next step.
I was trying to figure it out with awk but wasnt working well.
Never mind, found answer. did not know about tr :) (7 Replies)
Hello All,
I am trying to remove all tabspaces and all blankspaces from my file using sed & awk, but not getting proper code. Please help me out.
My file is like this (<b> means one blank space, <t> means one tab space)-
$ cat file
NARESH<b><b><b>KUMAR<t><t>PRADHAN... (3 Replies)
Hello all,
I want to list the file contents of the directory and number them. I am using la and awk to do it now,
#ls |awk '{print NR "." $1}'
1. alpha
2. beta
3. gamma
The problem I have is that some files might also have some spaces in the filenames.
#ls
alpha beta gamma ... (7 Replies)
How to print the strings within a line between two spaces .
<ns1:providerErrorCode>141</ns1:providerErrorCode> <ns1:providerErrorText>business_rule_exception-Server.404:Cannot proceed because the subscriber with phone number is either suspended or the account has an unpaid... (8 Replies)
When I use:
find . -ls | awk 'BEGIN { OFS = ";"} {print $1,$2,$11}'I get a nice result, yet the files with spaces in it show only the first word and all other characters after the blank space are not printed.
e.g. 'file with a blank space'
is printed
file
'file_with a blank space'
is... (7 Replies)
I have a one-line command,
lsusb | awk '{ $1=""; $2=""; $3=""; $4=""; $5=""; $6=""; print $0 }'
It works, and gives the results I expect, I was just wondering if I am missing some easier way to nullify the first 6 column variables?
Something like,
lsusb | awk '{ $(1-6)=""; print $0 }'
But... (10 Replies)
Hi,
I'm using awk to print columns from a tab delimited text file:
awk '{print " "$2" "$3" $6"}' file
The problem I have is column 6 contains text with spaces etc which means awk only prints the first word.
How can I tell awk to print the whole column content as column 6?
Thanks, (10 Replies)
Discussion started by: keenboy100
10 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)