Sponsored Content
Top Forums UNIX for Advanced & Expert Users Need help to extract part of the string Post 302943915 by RavinderSingh13 on Thursday 14th of May 2015 03:19:23 AM
Old 05-14-2015
Hello lkeswar,

Please use code tags for commands/codes used in your posts as per forum rules. Following may help you in same.

i-
Code:
echo "20140412-s1-Potopolive_promos_20140412" | awk '{sub(/.*-/,X,$0);sub(/_.*/,X,$0);print}'

ii-
Code:
A="20140412-s1-Potopolive_promos_20140412"
B=`echo ${A##*-}`
echo ${B%%_*}

Output will be same in both the cases, hope this helps.


Thanks,
R. Singh
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Extract Part of string from 3rd field $3 using AWK

I'm executing "wc -lc" command in a c shell script to get record count and byte counts and writing them to a file. I get the result with the full pathname of the file. But I do not want the path name to be printed in the output file. I heard that using Awk we can get this but I don't have any... (4 Replies)
Discussion started by: stakuri
4 Replies

2. UNIX for Dummies Questions & Answers

Extract a part of file name

Hi, I want to extract a part of filename and pass it as a parameter to one of the scripts. Could someone help. File name:- NLL_NAM_XXXXX.XXXXXXX_1_1.txt. Here i have to extract only XXXXX.XXXXXXX and the position will be constant. that means that i have to extract some n characters from... (6 Replies)
Discussion started by: dnat
6 Replies

3. Shell Programming and Scripting

extract last part of string.

Hi, I have a string like this BUNDLE=/home/bob/flx/user.bun how to extract only the the last part ie, only user.bun (2 Replies)
Discussion started by: vprasads
2 Replies

4. Shell Programming and Scripting

How to extract one part from whole output

Hi All, I am trying to write a small shell programming to get db2 database size info. The command I am going to use is- db2 "CALL GET_DBSIZE_INFO(?, ?, ?, -1)" and the output of above command generally is- Value of output parameters -------------------------- Parameter Name :... (4 Replies)
Discussion started by: NARESH1302
4 Replies

5. Shell Programming and Scripting

how to extract a certain part of a line

Hi friends, I want to select and use the certain part of a line. For example I have the following line home/1245/hgdf/acsdf/myhome/afolder/H2O/endfile how can I extract the part " /myhome/afolder/H2O/endfile " thanks (6 Replies)
Discussion started by: rpf
6 Replies

6. Shell Programming and Scripting

Help with extract particular part of data

Input file <data> <temporary>qe2qrqerq qwewqeqwrqwrq qrerwrewrwer </temporary> </data> <sample>@!@##%#</sample> <info>12345</info> <content>2313214141454</content> <data> <temporary>qe2qrqerq qrerwrewrwer </temporary> <content>123214214523</content> </data>... (5 Replies)
Discussion started by: perl_beginner
5 Replies

7. Shell Programming and Scripting

extract part of string using sed

Hi, I have the following string and I need to extract the date from it: TextHere,2012/07/11,1 I tried using sed: sed -n 's#^.*\({4}/{2}/{2}\).*$#\1#p' But it doesn't return anything. The following line doesn't even return '2012': sed -n 's/^.*\({4}\).*$/\1/p' I used to use grep -o... (6 Replies)
Discussion started by: Subbeh
6 Replies

8. Shell Programming and Scripting

Extract part of a string

I have a file with 100s of lines of text. I want to perform an extraction of this line: Info bpzs(pid=2652) using 1000 bits I have not been able to extract it. Should I try expr match or is there another method? This line has data both in front of and in back of it. I do not have grep -o... (5 Replies)
Discussion started by: newbie2010
5 Replies

9. Shell Programming and Scripting

Extract number part from the string in ksh 88

I have to extract number part (Date and timestamp part ) from the following 3 strings AB_XYZA_20130930183017.log AB_DY_XYZA_20130930183017.log AB_GZU_20130930183017.log Output should be 20130930183017 Please help me to get the string like above Thanks (2 Replies)
Discussion started by: smile689
2 Replies

10. Shell Programming and Scripting

How to extract part of string from all log files.?

Hi All, Let us say we have 5 log files, extract the data from all log files and save the output in a file. home/log/first.log home/log/second.log home/log/third.log home/log/four.log home/log/five.log I want to extract the following text from the log files and save the output in a file.... (7 Replies)
Discussion started by: ROCK_PLSQL
7 Replies
MU-EXTRACT(1)						      General Commands Manual						     MU-EXTRACT(1)

NAME
mu_extract - display and save message parts (attachments), and open them with other tools. SYNOPSIS
mu extract [options] <file> mu extract [options] <file> <pattern> DESCRIPTION
mu extact is the mu sub-command for extracting MIME-parts (e.g., attachments) from mail messages. It works on message files, and does not require the message to be indexed in the database. For attachments, the file name used when saving it, is the name of the attachment in the message. If there is no such name, or when saving non-attachment MIME-parts, a name is derived from the message-id of the message. If you specify a pattern (a case-insensitive regular expression) as the second argument, all attachments with filenames matching that pat- tern will be extracted. The regular expressions are Perl-compatible (as per the PCRE-library). Without any options, mu extract simply outputs the list of leaf MIME-parts in the message. Only 'leaf' MIME-parts (including RFC822 attach- ments) are considered, multipart/* etc. are ignored. OPTIONS
-a, --save-attachments save all MIME-parts that look like attachments. --save-all save all non-multipart MIME-parts. --parts=<parts> only consider the following numbered parts (comma-separated list).The numbers for the parts can be seen from running mu extract without any options but only the message file. --target-dir=<dir> save the parts in the target directory rather than the current working directory. --overwrite overwrite existing files with the same name; by default overwriting is not allowed. --play Try to 'play' (open) the attachment with the default application for the particular file type. On MacOS, this uses the open program, on other platforms is uses xdg-open. You can choose a different program by setting the MU_PLAY_PROGRAM environment variable. EXAMPLES
To display information about all the MIME-parts in a message file: $ mu extract msgfile To extract MIME-part 3 and 4 from this message, overwriting existing files with the same name: $ mu extract --parts=3,4 --overwrite msgfile To extract all files ending in '.jpg' (case-insensitive): $ mu extract msgfile '.*.jpg' To extract an mp3-file, and play it in the the default mp3-playing application. $ mu extract --play msgfile 'whoopsididitagain.mp3' BUGS
Please report bugs if you find them: http://code.google.com/p/mu0/issues/list AUTHOR
Dirk-Jan C. Binnema <djcb@djcbsoftware.nl> SEE ALSO
mu(1) User Manuals February 2012 MU-EXTRACT(1)
All times are GMT -4. The time now is 01:46 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy